PLEASE HELP ME WITH THIS BOTH A.S.A.P I WELL GIVE 20 POINTS AND A BRAINLIST FOR THE BEST EXPLANATION

Mathematics

1 answer:

Stella [2.4K]3 years ago

3 0

Answer: yes they are

Step-by-step explanation: the way you know is because the angles on each shape are the same and the lines on the shapes are the same length. If one shape is bigger than another or if one has a different shape than the other, they are not congruent. I hope that helped you!

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Flura [38]

This is more than one question.

3 0

3 years ago

A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title

kirill [66]

$y' = \frac{dy}{dx}$

seperable differential equations will have the form
$\frac{dy}{dx} = F(x) G(y)$

what you do from here is isolate all the y terms on one side and all the X terms on the other
$\frac{dy}{G(y)} = F(x) dx$
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
$\int \frac{1}{G(y)} dy = \int F(x) dx

$

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it

In your problem,
$G(y) = \sqrt{1-y^2}

F(x) = 2x$

so all you need to integrate is
$\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx$