Question

The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1). Find the new coordinates of the vertices after the given translation. (x, y) → (x + 3, y − 1) A) A(−2, 0), B(0.5, 6), C(3, 0) B) A(−2, 0), B(0.5, 6), C(0, 3) C) A(−8, 2), B(5.5, 6), C(−3, 2) D) A(2, 0), B(−0.5, 6), C(−3, 0)

Answer 1

Answer: A'(-2, 0), B'(0.5, 6), C'(3, 0)

Step-by-step explanation:

Given : The vertices of triangle ABC are A(−5, 1), B(−2.5, 7), and C(0, 1).

The rule of translation:

$(x,y)\rightarrow\ (x+3,\ y-1)$

Then , the new coordinates of the image will be :-

$A(-5,1)\rightarrow\ A'(-5+3,\ 1-1)=A'(-2,\ 0)$

$B(-2.5, 7)\rightarrow\ B'(-2.5+3,\ 7-1)=B'(0.5,\ 6)$

$C(0, 1)\rightarrow\ C'(0+3,\ 1-1)=C'(-3,\ 0)$

Hence, the new coordinates of the vertices after the given translation. :

A'(-2, 0), B'(0.5, 6), C'(3, 0)

Answer 2

Hello from MrBillDoesMath!

Answer:

Choice A

Discussion:

A = (-5,1)                   --- under translation => (-5 + 3, 1-1) = (-2,0)

B = (-2.5, 7)             --- under translation =>  (-2.5 + 3, 7 - 1) = (.5, 6)

C =   (0,1)                  --- under translation =>  (0+3, 1-1) = ( 3,0)

This is Choice A

Thank you,

MrB