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Fudgin [204]
3 years ago
11

What is the answer to 1+1?

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Brainliest me pls

Have a nice Day!

vodomira [7]3 years ago
3 0

Answer:

The answer is 2

Step-by-step explanation:

1+1=2

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Step-by-step explanation:

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You can write a as their meet point . you should answer like this a(2,4) .

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PLEASE SHOW ALL YOUR WORK TO GET BRAINLIEST AWARD
krek1111 [17]
<span> 7x+2y=5;13x+14y=-1 </span>Solution :<span><span> {x,y} = {1,-1}</span>  </span>System of Linear Equations entered :<span><span>  [1] 7x + 2y = 5 </span><span>  [2] 13x + 14y = -1 </span></span>Graphic Representation of the Equations :<span> 2y + 7x = 5 14y + 13x = -1 </span>Solve by Substitution :

// Solve equation [2] for the variable  y  
 

<span> [2] 14y = -13x - 1 [2] y = -13x/14 - 1/14</span>

// Plug this in for variable  y  in equation [1]

<span><span>  [1] 7x + 2•(-13x/14-1/14) = 5 </span><span>  [1] 36x/7 = 36/7 </span><span>  [1] 36x = 36 </span></span>

// Solve equation [1] for the variable  x  

<span><span>  [1] 36x = 36</span>  <span>  [1] x = 1</span> </span>

// By now we know this much :

<span><span>  x = 1</span> <span>  y = -13x/14-1/14</span></span>

<span>// Use the  x  value to solve for  y  
</span>

<span>   y = -(13/14)(1)-1/14 = -1 </span>Solution :<span><span> {x,y} = {1,-1}</span>  <span> Processing ends successfully</span></span>
8 0
3 years ago
Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0
guajiro [1.7K]

Answer:

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

\displaystyle -3x^4+27x^2+1200=0

If we call y=x^2, our equation becomes a second-degree equation

\displaystyle -3y^2+27y+1200=0

Dividing by -3

\displaystyle y^2-9y-400=0

Factoring

\displaystyle (y-25)(y+16)=0

It leads to these solutions

\displaystyle y=25\ ,\ y=-16

Taking back the change of variable, we have for the first solution

\displaystyle x^2=25\Rightarrow x=-5,x=5

Now for the second solution, we get imaginary (complex) values

\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i

Summarizing, the four solutions for x are

\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i

5 0
3 years ago
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