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vazorg [7]
3 years ago
10

Last Saturday there were 1486 people at the Cineplex there were about the same number of people in each of six theaters between

which two numbers does the number of people in each theater fall
Mathematics
2 answers:
lions [1.4K]3 years ago
7 0
I do believe between 247 and 248
Gre4nikov [31]3 years ago
6 0

Answer: The required two number will be 247 and 248.

Step-by-step explanation:

Since we have given that

Number of people at the Cineplex  on last Saturday=1486

Number of theaters are there=6

Number of people in each theatres is given by

\frac{1486}{6}=247.66

So it must lie between 247 and 248.

As the number of people in each theatre is  247.66 so , it may be between 247 and 248.

So, the required two number will be 247 and 248.


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Find the missing segment in the image below​
Bogdan [553]

Answer:

3

Step-by-step explanation:

Intercept theorem

DE // CB ⇒ \frac{AD}{AC} = \frac{AE}{AB}

⇒ \frac{6}{6+?} =\frac{4}{4+2}

⇒ ? = 3

7 0
3 years ago
In a GP the second and fourth terms are 0.04 and I respectively find the common ratio and the first term​
Reptile [31]

Answer:

common ratio=0.5, a1= 0.08

Step-by-step explanation:

r=a3/a2

r=a4/a3

compare both we get:

a3/a2=a4/a3

subtitute a2=0.04 and a4=1

a3/0.04=1/a3

(a3)^2=0.04*1

(a3)^2=0.04

taking square root in both sides

a3=0.02

For r, r=a3/a2

subtitute a3 and a2 above

r=0.02/0.04

r=0.5 common ratio

For a1

r=a2/a1

0.5=0.04/a1

a1=0.04/0.5

a1=0.08

4 0
3 years ago
At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening
pav-90 [236]

Answer:

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

p_v =2*P(z>4)=0.0000633  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation  

\bar X=23 represent the sample mean

\sigma=3.5 represent the population standard deviation

n=49 sample size  

\mu_o =21 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

Null hypothesis:\mu = 21  

Alternative hypothesis:\mu \neq 21  

The statistic is given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>4)=0.0000633  

Conclusion  

When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

8 0
3 years ago
A line has a y-intercept and a slope of 0. What is the line’s equation?
Gnom [1K]
The answer is y= -1

When the slope is 0, we refer to the line as a constant function. In slope intercept form, the line is equal to y = mx + b

 

"m" is the slope, and "b" is the y-intercept.

 

Let's replace those in the function.

 

y = 0*x - 1

 

0 multiplied by anything is 0

 

y = 0 - 1

y = -1

6 0
3 years ago
Shelly rolls a number cube labeled from 1 to 6. What is the probability that she rolls a number greater than 5 or less than 2?
s2008m [1.1K]

Answer:

1/3 =0.33 = 33%

Step-by-step explanation:

The probability is the number of chances divided by the total number. The total number of options is 6 since it is a six sided cube. She could roll a 6 to be greater than 5 or 1 to get less than 2. These are two options out of  total of 6.

2 out of 6 is 2/6 which simplifies to 1/3 =0.33 = 33%

7 0
3 years ago
Read 2 more answers
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