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2 years ago

I need help with this question please and thank you

Mathematics

1 answer:

finlep [7]2 years ago

7 0

Answer:

Bubble A. Matter!

Step-by-step explanation:

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Cual es la fraccion equivalente de 105/275

xxMikexx [17]

Answer:

21/55

Step-by-step explanation:

dividamos por 5

= 21/55

3 0

2 years ago

What single discount is equal to a discount of 1/4 off followed by an additional 10% off the sale price?

White raven [17]

Original is 100
1/4 off is 25 off
75 left
10% what's left is 75-7.5=67.5

this was already out of 100

100=67.5=32.5

1/4 off and then 10% off is the same as 32.5% discount

4 0

3 years ago

At Baceball practice, Asher caught 16 of 20 hits to the out field. Select all of the was of expressing 16 out of 20. a. 3/5 b. 0

kvasek [131]

Answer:

16 : 20 = 0,8 = 80%

Step-by-step explanation:

pls make me a brinist

3 0

3 years ago

At a certain factory 10% of staplers produced on Monday were defective and 2% of the non defective staplers were rejected by mis

Leni [432]

Answer: 4500

Step-by-step explanation:

Let x be the total number of staplers produced in a day.

Given : At a certain factory 10% of staplers produced on Monday were defective and 2% of the non defective staplers were rejected by mistake.

i.e. The probability of staplers non defective staplers were rejected by mistake = 0.02

Now, If 90 of the non defective staplers were rejected, then to find the total number of staplers produced that days is given by :-

$0.02x=90\\\\\Rightarrow\ x=\dfrac{90}{0.02}=4500$

Hence, the total number of staplers produced that day is 4500.

3 0

3 years ago

The article " Inconsistent Health Perceptions for US Women and Men with Diabetes" presents results of a survey of adults with di

musickatia [10]

Answer:

The 99% confidence level (-0.741, -0.659).

Step-by-step explanation:

The average body mass index (BMI) in a sample of 1559 men was 30.4, with a standard deviation of 0.6.

The average BMI in a sample of 1924 women was 31.1 with a standard deviation of 0.2.

Find a 99% confidence interval for the difference between the mean weights..

The formula for 99% Confidence Interval for difference between the mean weights =

μ is the population mean, and σ is the population standard deviation.

μ1 - μ2 ± z × √σ²1/n1 + σ²2/n2

The z score for 99% confidence interval = 2.576

30.4 - 31.1 ± 2.576 × √0.6²/1559 + 0.2²/1924

-0.7 ± 2.576 × √0.36/1559 + 0.04/1924

-0.7 ± 2.576 × √0.0002309173 + 0.00002079

-0.7 ± 2.576 ×√0.0002517073

-0.7 ± 2.576 × 0.015865286

-0.7 ± 0.04086897674

Hence, the 99% Confidence Interval is

-0.7 - 0.04086897674

= -0.74086897674

≈ -0.741

-0.7 + 0.04086897674

=-0.65913102326

≈ -0.659

Therefore, the 99% confidence level (-0.741, -0.659).

5 0

2 years ago