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3 years ago

What is the probability that a person who is above 35 years old has a hemoglobin level of 9 or above?

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

4 0

Answer:

Option C. $P=0.531$

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space (total person's hemoglobin level of 9 or above with age above 35 years)

y-----> size of the sample space (total person's age above 35 years)

$P=\frac{x}{y}$

In this problem we have

$y=162$

Complete the table to find the total person's hemoglobin level of 9 or above (person's age above 35)

Let

y------> total person's hemoglobin level between 9 and 11 (person's age above 35)

$y+76+40=162$

$y=46$

Find the value of x

$x=46+40=86$

substitute the values

$P=\frac{86}{162}=0.531$

earnstyle [38]3 years ago

3 0

Answer:

The answer is C. 0.531

Step-by-step explanation:

Because

76+x+40= 162.

x= 162-76-40

x= 46

Hence,

40+46=86.

Therefore, probability that a person who is above 35 years old has a hemoglobin level of 9 or above is,

86/162= 0.531.

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Evaluate this exponential expression.

Levart [38]

Answer:

$(-27)^\dfrac{2}{3}$ = 9

Step-by-step explanation:

Given that,

Asn expression : $(-27)^\dfrac{2}{3}$

We need to evaluate the above expression.

We know that, $(-3)^3=-27$

So,

$(-27)^\dfrac{2}{3}=(-3)^{3\times \dfrac{2}{3}}$

$=(-3)^2\\\\=-3\times -3\\\\=9$

So, the value of $(-27)^\dfrac{2}{3}$ is 9. Hence, the correct option is (b).

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3 years ago

I need help please and thank you

Brums [2.3K]

Well I THINK triangle ABC is just a stretched out version of triangle DEF.

To find the area of a triangle, you multiply base and height, and divide by 2.

Area of DEF is 6, so that means that (4 * x)/2 = 6.

6*2 = 12....

4 * x = 12........

4 * 3 = 12.

x = 3.

Comparing DEF to ABC: ABC's base is 3 times as long as DEF's. So that means the height must be three times as long.

3*3 = 9.

(12 * 9)/2 =54

5 0

3 years ago

Read 2 more answers

What’s the area?<br> yahshjsjsjshshjdjxndndn

algol13

Answer:

10 sq units

Step-by-step explanation:

The area of a triangle is 1/2bh

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2 years ago

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Which expression is equivalent

Tatiana [17]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

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3 years ago

A couple purchased a home and signed a mortgage contract for $900,000 to

Tema [17]

9514 1404 393

Answer:

$33,336.83
$35,176.68
$36,869.23
$38,266.75
$39,158.08

Step-by-step explanation:

The amortization formula can be used to find the payment value.

A = P(r/2)/(1 -(1 +r/2)^(2n))

where P is the principal amount at the beginning of the loan period, r is the annual interest rate, n is the number of years remaining on the loan

The value of A in this scenario is the semi-annual payment.

Initially, the interest rate is 0.055 and the number of years remaining is 25.

After the first 5-year period, the interest rate goes up by 12%, so is multiplied by a factor of 1.12 to become 6.16% per year. The same growth factor is applied to the interest rate at the beginning of each 5-year period.

Of course, the number of years remaining is decreased by 5 years at the beginning of the next 5-year period.

The Principal remaining at the end of each 5-year period is the starting principal for the next period. It is calculated from ...

FV = P(1 +r/2)^10 -A((1 +r/2)^10 -1)/(r/2)

Where P is the starting principal, A is the loan payment as calculated above, and r is the annual interest rate.

These formulas are built into spreadsheet functions, so the desired set of loan payments can be calculated easily by that technology. The result is attached. In the "# pmts" column is the value used to amortize the loan for the 5-year period. The semiannual payment is calculated as though the loan would be completely paid off in that number of payments, keeping the same interest rate for the duration. Of course, that payment series is interrupted and the loan recalculated at the beginning of the next 5 years.

The half-yearly payments for each 5-year interval are ...

$33,336.83

$35,176.68

$36,869.23

$38,266.75

$39,158.08

_____

<em>Additional comment</em>

The values displayed in the spreadsheet are rounded to the values shown. The values used in calculation have 14 or more significant digits. This means the numbers here may vary from those provided by a lending institution. In the real world, the principal and interest values are rounded to cents with each payment, so actual results may vary by a few cents either way.

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3 years ago