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Illusion [34]
3 years ago
15

The volume of a cone is 141.3 cubic inches. The height of the cone is 15 inches. What is the radius of the cone, rounded to the

nearest inch? Use π = 3.14.
 2 inches
 3 inches
 5 inches
 9 inches
Mathematics
2 answers:
jeka943 years ago
6 0
The Answer is 3 Inches.
The Equation is 15×9×3.14÷3=141.3 cubic inches(volume)
The Formula is h×r²×π÷3=V
Damm [24]3 years ago
6 0

Answer:

The answer is 3 inches.

Step-by-step explanation:

The Equation is 15×9×3.14÷3=141.3 cubic inches(volume)

The Formula is h×r²×π÷3=V

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Suppose f(x) = x³ . find the graph of f(x+5)
Ganezh [65]
\bf ~~~~~~~~~~~~\textit{function transformations}
\\\\\\
% templates
f(x)=  A(  Bx+  C)+  D
\\\\
~~~~y=  A(  Bx+  C)+  D
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f(x)=  A\sqrt{  Bx+  C}+  D
\\\\
f(x)=  A(\mathbb{R})^{  Bx+  C}+  D
\\\\
f(x)=  A sin\left( B x+  C  \right)+  D
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--------------------

\bf \bullet \textit{ stretches or shrinks horizontally by  }   A\cdot   B\\\\
\bullet \textit{ flips it upside-down if }  A\textit{ is negative}\\
~~~~~~\textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }  B\textit{ is negative}

\bf ~~~~~~\textit{reflection over the y-axis}
\\\\
\bullet \textit{ horizontal shift by }\frac{  C}{  B}\\
~~~~~~if\ \frac{  C}{  B}\textit{ is negative, to the right}\\\\
~~~~~~if\ \frac{  C}{  B}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }  D\\
~~~~~~if\   D\textit{ is negative, downwards}\\\\
~~~~~~if\   D\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{  B}

and with that template in mind,

notice from a parent function of   f(x) = x³,
a derived function with f(x+5) = (x + 5)³

has a C component of 5, C = 5, which means is the as the parent, just shifted to the left by 5 units.
5 0
4 years ago
Read 2 more answers
Twenty-seven minus 3/2of a number (x) is not more than 36. What is the number?
Zigmanuir [339]

Twenty-seven minus 3/2of a number (x) is not more than 36.

27 - (3/2)X = 36

What is the number?

(3/2)X = 27 - 36 = - 9

X = (- 9x2)/3 = -18/3 = -6

Check

36 = 27 - (3/2)X =  27 - (3/2)x(-6) = 27 - (-18/2) = 27 - (-9) = 36

5 0
3 years ago
What is the slope of a line that passes through (-4,-13) and (19,11)?
raketka [301]
We can find the slope from the two given points using the standard formula:
m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}
m=\frac{11-(-13)}{19-(-4)}
m=\frac{24}{23}
7 0
3 years ago
Select all pairs of numbers that have a least common multiple of 30.
ddd [48]

5 and 6  and 3 and 10, the pairs of numbers that have a least common multiple of 30.

<u>Step-by-step explanation:</u>

Case 1: LCM (3, 6)

Prime factorization of 3:  1 \times 3

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

               2 \times 3=6

Therefore LCM (3, 6) = 6.

Case 2: LCM (5, 6)

Prime factorization of 5:  1 \times 5

Prime factorization of 6:  2 \times 3

Using all prime numbers found as often as each occurs most often we take

                     5 \times 2 \times 3=30

Therefore LCM (5, 6) = 30

Case 3: LCM (3, 10)

Prime factorization of 3:  1 \times 3

Prime factorization of 10:  2 \times 5

Using all prime numbers found as often as each occurs most often we take

                    5 \times 2 \times 3=30

Therefore LCM (3, 10) = 30

Case 4: LCM (5, 10)

Prime factorization of 5:  1 \times 5

Prime factorization of 10: 2 \times 5

Using all prime numbers found as often as each occurs most often we take

                       5 \times 2=10

Therefore LCM (5, 10) = 10

8 0
3 years ago
PLEASE HELP!!!!! HAVING TROUBLE <br><br> (see attached images)
qaws [65]

Answer:

The Proof for

Part C , Qs 9 and Qs 10  is below.

Step-by-step explanation:

PART C .

Given:

AD || BC ,

AE ≅ EC

To Prove:

ΔAED ≅ ΔCEB

Proof:

Statement                             Reason

1. AD || BC                           1. Given

2. ∠A ≅ ∠C                        2. Alternate Angles Theorem as AD || BC

3. ∠AED ≅ ∠CEB               3. Vertical Opposite Angle Theorem.

4. AE ≅ EC                        4. Given

5. ΔAED ≅ ΔCEB              5. By A-S-A congruence test....Proved

Qs 9)

Given:

AB ≅ BC ,

∠ABD ≅ ∠CBD

To Prove:

∠A ≅ ∠C

Proof:

Statement                             Reason

1. AB ≅ BC                        1. Given

2. ∠ABD ≅ ∠CBD            2. Given      

3. BD ≅ BD                       3. Reflexive Property

4. ΔABD ≅ ΔCBD             4. By S-A-S congruence test

5. ∠A ≅ ∠C                       5. Corresponding parts of congruent Triangles Proved.

Qs 10)

Given:

∠MCI ≅ ∠AIC

MC ≅ AI

To Prove:

ΔMCI ≅ ΔAIC

Proof:

Statement                             Reason

1. ∠MCI ≅ ∠AIC       1. Given

2. MC ≅ AI              2. Given

3. CI ≅ CI                3. Reflexive Property

4. ΔMCI ≅ ΔAIC     4. By S-A-S congruence test

4 0
3 years ago
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