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postnew [5]
1 year ago
10

Which of the following is equivalent to “the quotient of 30 and the difference of 12 and 6”?

Mathematics
2 answers:
Afina-wow [57]1 year ago
4 0

Answer:

Option D, \frac{30}{12-6}

Step-by-step explanation:

<u>Step 1:  Determine the correct expression</u>

So we know for sure that we will be doing 12 - 6 because we have the part where it says the difference of 12 and 6.  That leaves us with Options A and D.  Looking back at the statement we can see that the quotient of 30 and the rest which means that 30 would be the numerator and located at the top.  This gives us option D.

Answer: Option D, \frac{30}{12-6}

mars1129 [50]1 year ago
3 0

Answer:

D. \frac{30}{12-6}

Step-by-step explanation:

We can immediately eliminate choices B and C because B shows "the difference of 6 and 12", not "of 12 and 6", and C shows "the quotient of 30 and 12 minus 6." 12 and 6 are not being subtracted properly.

30 is being stated before the difference of 12 and 6, so the difference will be the divisor, and 30 will be the dividend, therefore it will go in the <u>numerator</u>.

The only option that fits this criteria is D, so that is the answer.

hope this helps :)

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aleksley [76]

Answer:

<h2>y = -5x - 10</h2>

Step-by-step explanation:

\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================

\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10

7 0
3 years ago
PLEASE HELP ME!!
Dmitry_Shevchenko [17]
I think it’s A sorry if it’s wrong!
6 0
2 years ago
4²+A = can someone simplify this please
snow_lady [41]

Answer:

16+A

Step-by-step explanation:

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7 0
2 years ago
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HELP ME RN PLEASEEEE<br> [WILL GIVE BRAINLY TO CORRECT AND BEST EXPLAINED ANSWER]
VMariaS [17]

Answer:

\boxed {\boxed {\sf d= \sqrt{34}}}

Step-by-step explanation:

We want to find the distance between two points, so the following formula is used.

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Where (x₁, y₁) and (x₂, y₂) are the points we are finding the distance between.

We are given the points (-2, -1) and (3,2). If we match the corresponding value and variable we see that:

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Substitute the values into the formula.

d= \sqrt {(-2-3)^2+(2--1)^2

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Solve the exponents.

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d= \sqrt{25+9}

Add.

d= \sqrt{34}

This radical cannot be simplified, so the distance between the two points is <u>√34</u> and <u>choice 3 </u> is correct.

6 0
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