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amm1812
3 years ago
6

What is the maximum possible value of 18.6?

Mathematics
1 answer:
yan [13]3 years ago
5 0
The minimum value is 18.55 and the maximum value is 18.64. When rounding to one decimal place, you must look at the number two places after the decimal. If this is bigger than 5 round up and lower than 4 round down.
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A quantity p varies jointly with r and s. Which expression represents the constant of variation, k?
Zina [86]

The correct answer is p/rs.

In order to find this first state the direct variation with the constant k included.

p = krs

Now to find the value of k, we simply divide away the r and s

p/rs = k

3 0
3 years ago
Read 2 more answers
Elect two ratios that are equivalent to 6 : 10
Vika [28.1K]
Answer is :
12:20
18:30
7 0
3 years ago
How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t
Zarrin [17]

By first principles, the derivative is

\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h

Use the binomial theorem to expand the numerator:

(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n

(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

The first term is eliminated, and the limit is

\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h

A power of h in every term of the numerator cancels with h in the denominator:

\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)

Finally, each term containing h approaches 0 as h\to0, and the derivative is

y=x^n\implies y'=nx^{n-1}

4 0
3 years ago
Bella has 6.3 kilograms of berries.she packs 0.35 kilogram of berries into each container.she then sells each container for 2.99
yKpoI14uk [10]
6.3 / 0.35 = 18
18 x 2.99 = $53.82
7 0
3 years ago
Read 2 more answers
Can anyone answer this
erik [133]

Answer:

Step-by-step explanation:

1. 10² + 7² = x²

 149 = x²

 x = √149

2. x² + 19² = 21²

 x² = 21² -  19² = 80

 x = √80 = 4√5

3. x² + 16² = 27²

 x² = 27² - 16² = 473

 x = √473

4. 5.3² + 12.8² = x²

 191.93 = x²

 x = √191.93

5. 9² + 20² = x²

 481 = x²

 x = √481

6. 31 = x + 2√(19²-17²) = x + 2·6√2 = x + 12√2

 x = 31 - 12√2

 

5 0
3 years ago
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