(−m)(n)p(3m−5n+7p)
=((−m)(n)p)(3m+−5n+7p)
=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)
=−3m^2np+5mn^2p−7mnp^2
Answer:
Third Option
Step-by-step explanation:
We know that the function 
is defined as 
. Since the denominator is 
then we know that 
when 
We also know that the division by 0 is not defined. Therefore, the limit of 
when "x" tends to 
is infinite.
The function 
is the inverse of
By definition, if we have a function f(x), its domain will be equal to the range of its inverse function 
. If 
, then 
This also happens for the function
If when 
then when 
Then, the answer is:
Answer:
x−2x4+2x3−7x2−8x+12=x3+4x2+x−6
The rational root theorem suggests that other possible roots may be -6, 6, -3, 3, -2, 2, -1, and 1. It turns out that x=-2x=−2 is a root, since (-2)^3+4(-2)^2+(-2)-6=0(−2)3+4(−2)2+(−2)−6=0 , so x+2x+2 is also a factor and we have
\dfrac{x^4+2x^3-7x^2-8x+12}{(x-2)(x+2)}=x^2+2x-3(x−2)(x+2)x4+2x3−7x2−8x+12=x2+2x−3
Finally, we can factorize the remaining quotient easily:
x^2+2x-3=(x+3)(x-1)x2+2x−3=(x+3)(x−1)
so the other factors are x+2x+2 , x+3x+3 , and x-1x−1 .
Answer:
they are 6 possibilities in one roll
Step-by-step explanation:
