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amm1812
3 years ago
6

What is the maximum possible value of 18.6?

Mathematics
1 answer:
yan [13]3 years ago
5 0
The minimum value is 18.55 and the maximum value is 18.64. When rounding to one decimal place, you must look at the number two places after the decimal. If this is bigger than 5 round up and lower than 4 round down.
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Find the product -mnp(3m-5n+7p)
allochka39001 [22]
(−m)(n)p(3m−5n+7p)

=((−m)(n)p)(3m+−5n+7p)

=((−m)(n)p)(3m)+((−m)(n)p)(−5n)+((−m)(n)p)(7p)

=−3m^2np+5mn^2p−7mnp^2

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each sentence shows the number of pages a student reads in a book and the amount of time it takes those pages to read .how many
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Step-by-step explanation:

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2 years ago
Which describes the behavior of the function f(x)= tan^-1(x)?
Fantom [35]

Answer:

Third Option

Step-by-step explanation:

We know that the function tan(x) is defined as y=\frac{sin(x)}{cos(x)}. Since the denominator is cos(x) then we know that  cos(x)=0  when x=\frac{\pi}{2}

We also know that the division by 0 is not defined. Therefore, the limit of y=tan(x) when "x" tends to \frac{\pi}{2} is infinite.

The function tan^{-1}(x) is the inverse of tan(x)

By definition, if we have a function f(x), its domain will be equal to the range of its inverse function f^{-1}(x). If f(3)=8, then f^{-1}(8)=3

This also happens for the function tan^{-1}(x)

If when x \to \frac{\pi}{2}, tan(x) \to \infty then when x \to \infty, tan^{-1}x \to \frac{\pi}{2}

Then, the answer is:

x \to \infty, f(x) \to \frac{\pi}{2}

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zysi [14]

Answer:

x−2x4+2x3−7x2−8x+12=x3+4x2+x−6

The rational root theorem suggests that other possible roots may be -6, 6, -3, 3, -2, 2, -1, and 1. It turns out that x=-2x=−2 is a root, since (-2)^3+4(-2)^2+(-2)-6=0(−2)3+4(−2)2+(−2)−6=0 , so x+2x+2 is also a factor and we have

\dfrac{x^4+2x^3-7x^2-8x+12}{(x-2)(x+2)}=x^2+2x-3(x−2)(x+2)x4+2x3−7x2−8x+12=x2+2x−3

Finally, we can factorize the remaining quotient easily:

x^2+2x-3=(x+3)(x-1)x2+2x−3=(x+3)(x−1)

so the other factors are x+2x+2 , x+3x+3 , and x-1x−1 .

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You roll a number cube.find each probability p(2)
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Answer:

they are 6 possibilities in one roll

Step-by-step explanation:

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