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4 years ago

What is the maximum possible value of 18.6?

1 answer:

5 0

The minimum value is 18.55 and the maximum value is 18.64. When rounding to one decimal place, you must look at the number two places after the decimal. If this is bigger than 5 round up and lower than 4 round down.
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X - 3y =17, -x - y=19 ???

Annette [7]

Answer: Its in the pic below

Step-by-step explanation: Hope this helps have a brilliant day- Lily ^_^

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3 years ago

Hey, if anyone is good at Algebra 2, please help with this problem! "The AP chemistry class is mixing 100 pints of liquid togeth

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2 years ago

Find a quadratic equation whose roots are 1.5 +√2 and 1.5-√2expressing it in the form of ax^2+bx+c+c=0 where a,b and c are integ

Ilia_Sergeevich [38]

0 = f(x) = (x - r)(x - s) = x² - (r+s) + rs

We have r=1.5+√2, s=1.5 -√2 so r+s = 3 and

rs = (1.5+√2)(1.5 - √2) = 1.5² - (√2)² = 2.25 - 2 = 0.25

f(x) = x² - 3x + -.25

For integer coefficients we mulitply by 4,

g(x) = 4f(x) = 4x² - 12x - 1

Answer: 4x² - 12x - 1 = 0

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3 years ago

A number cube is rolled 3 times.

Alex73 [517]

6....................

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3 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

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2 years ago