The insurance period must be chosen so that the probability of a microchip failure within that period is 4%. Reference to a standard normal distribution table shows that the z-score for a cumulative probability of 4% is -1.75.
Let the insurance period be X months:
-1.75 = (X - 93)/3.8
-6.65 = X - 93
X = 83.35 months.
The answer is 83.35 months.
Answer:
c(x)=(x+3)^2+5
Step-by-step explanation:
To complete the square, the same value needs to be added to both sides.
So, to complete the square x^2+6x+9=(x+3)^2 add 9 to the expression
C(x) =x^2 +6x + 9 + 14
Since 9 was added to the right-hand side also add 9 to the left-hand side
C(x) +9= x^2 +6x + 9 + 14
Using a^2 + 2ab + b^2=(a+b)^2, factor the expression
C(x)+9= (x+3)^2 +14
Move constant to the right-hand side and change its sign
C(x)=(x+3)^2 +14 - 9
Subtract the numbers
C(x)= (x+3)^2 +5
Well, the first line has a slope of -3, and runs through 0, -1.
a line parallel to that one, will have the same exact slope of -3.
now, we know about this other parallel line that it runs through -3,1, and of course, since is parallel, it has a slope of -3
![\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ &&(~ -3 &,& 1~) \end{array} \\\\\\ % slope = m slope = m\implies -3 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-1=-3[x-(-3)] \\\\\\ y-1=-3(x+3) \implies y-1=-3x-9\implies y=-3x-8](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccccccccc%7D%0A%26%26x_1%26%26y_1%5C%5C%0A%26%26%28~%20-3%20%26%2C%26%201~%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%25%20slope%20%20%3D%20m%0Aslope%20%3D%20%20m%5Cimplies%20-3%0A%5C%5C%5C%5C%5C%5C%0A%25%20point-slope%20intercept%0A%5Cstackrel%7B%5Ctextit%7Bpoint-slope%20form%7D%7D%7By-%20y_1%3D%20m%28x-%20x_1%29%7D%5Cimplies%20y-1%3D-3%5Bx-%28-3%29%5D%0A%5C%5C%5C%5C%5C%5C%0Ay-1%3D-3%28x%2B3%29%0A%5Cimplies%20%0Ay-1%3D-3x-9%5Cimplies%20y%3D-3x-8)
Answer: 
Step-by-step explanation:
You need to use the following Properties of Logarithms:
Given the following expression:
You can follow these steps in order to write it as a single logarightm:
- Apply the first property shown above:
- Apply the second property:
- Finally, apply the third property:
Solutions
We know that <span>a spinner was divided into many different color sectors. Some sectors are larger than others. The spinner was spun 300 times. The results were tallied up and were written in a table.
</span><span>Red:93
Blue:59
Green:105
Yellow:43
</span>
The spinner landed the highest on green. To find <span>the probability that the next spin will land on green we have add all the numbers and simplify them.
93 + 59 + 105 + 43 = 300
Out of 300 the spinner landed to green 105 times. We have the fraction 105/300.
105/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 15.
</span>We can reduce the fraction by dividing the numerator and denominator by the GCF = 15.
105 ÷ 15 = 7
300 ÷ 15 = 20
Our new fraction is 7/20
The <span>probability that the next spin will land on green is 7/20.
</span>≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡≡
<span>
To get the answer to part (B) we have to add the results of red and green then simplify.
93 + 105 = 198
The fraction is 198/300. </span><span>198/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 6.
</span>We can reduce the fraction by dividing <span>the numerator and denominator by the GCF = 6.
</span>198 ÷ 6 = 33
300 ÷ 6 = 50<span>
The new fraction is 33/50
</span>The probability that the next spin will land on either green or red is <span>33/50.
</span>
Hope this helps
