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exis [7]
2 years ago
13

This is the answer ...

Mathematics
1 answer:
Law Incorporation [45]2 years ago
7 0

yea that is right, not sure why it says it's wrong, I'm sorry must be so frustrating

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Here are the first five terms of an arithmetic sequence
Aneli [31]
3n+2

the difference between each term is 3 meaning it’s 3n. if you then take away 3 from the first term you are left with 2. this means the nth term is 3n+2
3 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
olga nikolaevna [1]

f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i

{x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4

The Lagrangian is

L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)

with partial derivatives (all set equal to 0)

L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}

for 1\le i\le n, and

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Substituting each x_i into the second sum gives

\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4

Then we get two critical points,

x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}

or

x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}

At these points we get a value of f(x_1,\cdots,x_n)=\pm2\sqrt n, i.e. a maximum value of 2\sqrt n and a minimum value of -2\sqrt n.

6 0
4 years ago
Which of the following equations is of a parabola with a vertex at (1, -2)?
Lapatulllka [165]

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3 years ago
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Nat2105 [25]

Answer: 6 4/5 pounds

Step-by-step explanation:

4 0
3 years ago
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A. AC because of how it is directly across from the Angle
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