To find the equation take the slope 2/3
y-y(1)=m(x-x(1)
y-4=2/3(x-8) = 2/3x-16/3
Next solve for y
y=2/3x-16/3 +4(turn 4 into a fraction with a common denominator)
y=2/3x-16/3 + 12/3
y=2/3x-4/3
Answer:
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
Step-by-step explanation:
In two similar triangles:
The ratio of the areas of two triangle is equal to the square of their perimeters.
Let A and A' represents the area of two triangles and P and P' represents their perimeter.
Then they are related as:

We are given:
A=72 dm^2 , A'=50 dm^2
and P+P'=226 dm.-----------(1)
i.e. 
on taking square root on both the side we get:

Now putting the value of P in equation (1) we obtain:

Hence,
P=226-102.7272=123.2727
Hence, the perimeter of the triangles are:
P=123.2727 dm
P'=102.7272 dm
Answer:
5/16m long.
Step-by-step explanation:
- 5/8 ÷ 2/1
- 5/8 × 1/2
- =5/16m long.
Answer:
h=(c/25)-4
Step-by-step explanation:
c-100 = 25h. "/25"
(c/25)-4 = h