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Vesna [10]
3 years ago
13

Select all the correct locations on the table.

Mathematics
1 answer:
zmey [24]3 years ago
7 0

Answer:

Situation 1 is exponential decay. Situation 2 is linear. Situation 3 is exponential growth.

Step-by-step explanation:

Situation 1 is exponential decay because it declined in a non linear way.

600-480=120 480-364=116

Situation 2 is linear because when it declined it has a dependent to another.

400-340=60 340-280=60

Situation 3 is exponential growth because is increases.

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A $4,000.00 principal earns 5% interest, compounded annually. After 4 years, what is the balance in the account?
alukav5142 [94]
4000(1.05)⁴=$4862.03

6000(1+ .08/2)^35(2)=$93429.71

15450(.86)³=$9827.07
8 0
3 years ago
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Find the area and the perimeter of the shaded regions below. Give
PolarNik [594]

Based on the definition of <em>composite</em> figure, the area of the <em>composite</em> figure ABC formed by a semicircle and <em>right</em> triangle is approximately 32.137 square centimeters.

<h3>How to find the area of the composite figure</h3>

The area of the <em>composite</em> figure is the sum of two areas, the area of a semicircle and the area of a <em>right</em> triangle. The formula for the area of the composite figure is described below:

A = (1/2) · AB · BC + (π/8) · BC²     (1)

If we know that AB = 6 cm and BC = 6 cm, then the area of the composite figure is:

A = (1/2) · (6 cm)² + (π/8) · (6 cm)²

A ≈ 32.137 cm²

Based on the definition of <em>composite</em> figure, the area of the <em>composite</em> figure ABC formed by a semicircle and <em>right</em> triangle is approximately 32.137 square centimeters.

To learn more on composite figures: brainly.com/question/1284145

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8 0
1 year ago
I need help with #39-42, please explain.
shusha [124]

For question 39 & 40, we need to use the below equation to complete the sentence

l=m\sqrt{n}

Question 39:

When ' n ' increase, the \sqrt{n} will also increase and that multiplied with constant ' m ', the l will also increase.

Solution for question 39:

As n increases and m stays constant , l <u>increases</u>

-------

Question 40:

Solving the equation for m, we get

l = m\sqrt{n} \\ \\ m=\frac{l}{\sqrt{n}}

When ' l ' increases, the numerator increase, the denominator stays constant because 'n' stays constant, for this condition, the fraction increases.

Solution for question 40:

As l increase and n stays constant, m <em><u>increases</u></em>

------

For question 41 & 42, we need to use the below equation to complete the sentence

r=s^2/t^2

Question 41:

When s is triped, the equation will be...

r=(3s)^2/t^2=\frac{3^{2}s^{2}}{t^2}   =9s^2/t^2

Solution for question 41:

If s is tripled and t stays constant, r is multiplied by <em><u>9</u></em>

--------

Question 42:

When t is doubled, the equation will be...

r=s^2/(2t)^2=\frac{s^2}{2^2 \cdot t^2}=\frac{s^2}{4t^2}\\   \\ r=0.25s^2/t^2 \; \; (or) \; \; \frac{1}{4} \cdot \frac{s^2}{t^2}

Solution for 42:

If t doubled and s stays constant, r is multiplied by <em><u>1/4 or 0.25</u></em>


3 0
3 years ago
Help please?? I’m being timed!!
weqwewe [10]

Answer:

answer is is option 3 all the best for examination

6 0
3 years ago
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2X minus one equals five
stepan [7]
2x-1=5
2(3)-1=5
6-1=5
5=5 

x=3
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3 years ago
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