All categories

3 years ago

Given thatX2: (20 – 3x) = 1 : 2find the possible values of x.

Mathematics

1 answer:

hammer [34]3 years ago

6 0

Answer:

Step-by-step explanation: x^2 : (20 - 3x) = 1 : 2

2x^2 + 3x - 20 = 0

(x + 4)(2x - 5) = 0

Solution:

x = -4

x = 5/2

You might be interested in

I still nee help with this q9

katen-ka-za [31]

Answer:

it is A

D"" (7,2)

6 0

3 years ago

Can anybody help me with this

Zolol [24]

For 4, the answer should be 3:1
To find that answer take 1.5 and divide it by 0.5

And for 5, the answer would be 3/4

6 0

3 years ago

Read 2 more answers

Please help !!!!!! thanks !!

navik [9.2K]

The intercept form of the equation is
x/x-intercept +y/y-intercept +z/z-intercept = 1
If you divide by 12, the equation can be written in intercept form as
x/3 +y/2 +z/6 = 1

The 1st selection is appropriate:
(3, 0, 0), (0, 2, 0), (0, 0, 6)

3 0

3 years ago

The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average

Reil [10]

Answer:

a) Null hypothesis : H₀ : μ = 5.5

Alternative Hypothesis : H₁ : μ < 5.5

b) The test statistic

|t| = |-3.33| = 3.33

c) P - value lies between in these intervals

0.001 < P < 0.005

Step-by-step explanation:

Step( i ):-

Given data the Population mean 'μ' = 5.5

The small sample size 'n' = 16

The sample mean (x⁻) = 5.25

Given the percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

Null hypothesis : H₀ : μ = 5.5

Alternative Hypothesis : H₁ : μ < 5.5

Level of significance ∝ = 0.01

Step(ii):-

The test statistic

$t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$t = \frac{5.25 -5.5}{\frac{0.3}{\sqrt{16} } }$

On calculation , we get

t = -3.33

|t| = |-3.33| = 3.33

Step(iii):-

P - value

The degrees of freedom γ = n-1 = 16-1 =15

The calculated value t = 3.33 (check t-table) lies between the 0.001 to 0.005

0.001 < P < 0.005

Condition(i)

P - value < ∝ then reject H₀

Condition(ii)

P - value > ∝ then Accept H₀

we observe that 0.001 < P < 0.005

P- value < 0.01

we rejected H₀

(or)

The tabulated value = 2.60 at 0.01 level of significance with '15' degrees of freedom

The calculated value t = 3.33 > 2.60 at 0.01 level of significance with '15' degrees of freedom

The null hypothesis is rejected

Conclusion:-

Accepted Alternative hypothesis H₁

The Claim that the true average is smaller than 5.5

4 0

3 years ago

Solve by factoring:4x^6+4x^5-24^4=0

Len [333]

Answer:

you could only get to “4x^6+4x^5-331776=0” that would be the simpliest form

Step-by-step explanation:

6 0

3 years ago

Given thatX2: (20 – 3x) = 1 : 2find the possible values of x.​

Given thatX2: (20 – 3x) = 1 : 2find the possible values of x.