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Nat2105 [25]
3 years ago
7

How to add it because I don not know how to do it

Mathematics
2 answers:
koban [17]3 years ago
7 0
   1              3            4
1 --    +    1 --   =    2 --
   5              5            5

Explanation:

1 + 1 = 2
1/5 + 3/5 = 4/5<span />
miss Akunina [59]3 years ago
3 0
1 + 3 = 4 1+1 = 2      the answer is 2 4/5
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X + 7 = 12 <br> i'm lost pls help me
andrezito [222]

Answer:

5

Step-by-step explanation:

12 - 7 = 5

x= 5

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8 0
3 years ago
6x - 2 = x + 13 what is the value of x
oksian1 [2.3K]

Answer:

x = 3

Step-by-step explanation:

6x - 2 = x + 13

6x - x = 13 + 2

5x = 15

x = 3

6 0
3 years ago
Finding the area of a regular polygon​
ddd [48]
<h2><u>Solu</u><u>tion</u><u>:</u></h2>

360° ÷ 10 ÷ 2 = 18°

So the length of the decagon side is:

10 × tan18° × 2 = 20 × tan18°

The area is: ½ × 20 × tan18° × 10 × 10 = 1000 × tan18°

≈ 324.9

.: <u>3</u><u>2</u><u>4</u><u>.</u><u>9</u> is the final answer.

<em>I</em><em> </em><em>h</em><em>ope</em><em> </em><em>this</em><em> helps</em><em>. </em>

5 0
2 years ago
Please solve this quickly !
Alja [10]

Answer:

AngleLOM=62°

AngleMON=15°

3 0
4 years ago
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
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