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ololo11 [35]
3 years ago
14

What is the distance between the two points (5,-2) and (-3,8)

Mathematics
1 answer:
bearhunter [10]3 years ago
4 0
You need to use the distance formula
d =  \sqrt{ {(x - x)}^{2}  +  {(y - y)}^{2} }

\sqrt{ {(5 + 3)}^{2}  +  {( - 2 - 8)}^{2} }
so the distance between points (5,-2) and (-3,8) is
2 \sqrt{41}
which won't simplify so it stays as is
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Step-by-step explanation:

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Factor:
nekit [7.7K]

Answer:

a) (7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)

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(ii) 14\cdot x^{2}-81 =(\sqrt{14}\cdot x+9)\cdot (\sqrt{14}\cdot x - 9)

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Step-by-step explanation:

Now we proceed to solve each algebraic equation:

a) Factor 49\cdot m^{12}-16

This binomial is of the form a^{2}-b^{2} = (a+b)\cdot (a-b). In this case, we can rewrite and factor the equation below:

49\cdot m ^{12}-16

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(7\cdot m^{6}+4)\cdot (7\cdot m^{6}-4)

b) Factor 49\cdot a^{2}\cdot b^{16}-1

This binomial is of the form a^{2}-b^{2} = (a+b)\cdot (a-b). In this case, we can rewrite and factor the equation below:

49\cdot a^{2}\cdot b^{16}-1

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c) Nicole is factoring 0.49\cdot t^{18}-25 by using the rule a^{2}-b^{2} = (a+b)\cdot (a-b). What will she use for the value of a?

From this rule we find that a^{2} = 0.49\cdot t^{18}, that is:

a^{2} = 0.49\cdot t^{18}

a^{2} = \frac{49}{100}\cdot t^{18}

a = \frac{7}{10}\cdot t^{9}

a = 0.7\cdot t^{9}

d) Which binomial is a difference of squares?

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(i) 16\cdot x^{2}-81 = (4\cdot x +9)\cdot (4\cdot x - 9)

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a^{6}-16

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Answer:

https://www.symbolab.com/solver/step-by-step/domain%20and%20range%20f%5Cleft(%C3%97%5Cright)%3D%202x%2F3x%2B2

Step-by-step explanation:

that will help you!

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Answer:

Step-by-step explanation:

3.1.1 What do you mean by SARS

Answer 3.1.2

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