Question

Hello there. May somebody help me simplify this problem? It would be very kind.

Answer 1

Answer:

27 / (4x⁶y⁸)

Step-by-step explanation:

$\frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}}$

When raised to a power, multiply the exponents.

$\frac{4(3^{3}x^{6}y^{12})}{2^{4}x^{12}y^{20}} \\\\\frac{2^{2}3^{3}x^{6}y^{12}}{2^{4}x^{12}y^{20}}$

When dividing, subtract the exponents.

$2^{2-4}3^{3}x^{6-12}y^{12-20}\\2^{-2}3^{3}x^{-6}y^{-8}$

Move negative exponents to the denominator.

$\frac{3^{3}}{2^{2}x^{6}y^{8}}\\\frac{27}{4x^{6}y^{8}}$