You would have to multiple the two factors to get the number as a product.
The formula of nth term is = 10 - 3n
What is AP?
- A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms. Take the numbers 5, 7, 9, 11, 13, and 15 as an example. . . is a sequence of numbers having a common difference of two.
- The n-th term of the sequence is given by:, if the beginning term of an arithmetic progression is and the common difference between succeeding members is, then
- If the AP contains m phrases, then denotes the final term, which is given by:
- The term "finite arithmetic progression" or "arithmetic progression" refers to a finite segment of an arithmetic progression. An arithmetic series is the total of a finite arithmetic progression.
Acc to our question-
- For the nth term in an algebraic series
- U(n) = a + (n - 1)d
- the number of terms is n.
- The first term is a.
- d is the typical difference
- From the preceding sequence
- a = 7
- d = 4 - 7 = - 3
- The nth term's formula is
- U(n) = 7 + (n - 1)-3
- = 7 - 3n + 3
- The ultimate solution is
- = 10 - 3n
Hence,The formula of nth term is = 10 - 3n
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Answer:
124250cm, 1242.5m or 1.2425km
Step-by-step explanation:
0.6% = 6/100
6/100 = 0.006
0.006*1.25 = 0.0075
1.25km = 1250m = 125000cm
0.0075km = 7.5m = 750cm
125000 - 750 = 124250
Therefore:
The answer is 124250cm, 1242.5m or 1.2425km
Sub to oTechz :)
Answer:
249 cm^2
Step-by-step explanation:
This problem becomes easier if we subdivide the figure, find the areas of the resulting figures and then sum them up.
Draw a vertical line straight down from the edge marked "4 cm" towards the edge marked "18 cm." The resulting rectangle on the left is 15.5 cm long and (18 - 7.5) cm wide, or 15.5 by 10.5 cm. Its area is 162.75 cm^2.
Next, find the area of the rectangle on the right of the line we drew. Its width is 7.5 cm and its height (15.5 - 4) cm, resulting in an area of 86.25 cm^2.
Last, add together these two subareas: combine 86.25 cm^2 and 162.75 cm^2. The total area of the composite figure is then 249 cm^2 (answer).
