Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
zero
Step-by-step explanation:
This flat horizontal line is Y=1 has a slope (rate of change) of zero.
Answer:
I'll try my best in explaining the steps.
Considering both signs are greater than and less than sign, its an open circle.
For the first equation, you would have an open circle, basically one that isn't colored in, on 8 on the number line. The arrow would be pointing to the left because the equation is telling us numbers that are less than 8.
For the second equation, you would have an open circle, basically one that isn't colored in, on -1 on the number line. The arrow would be pointing to the right because the equation is telling us numbers that are greater than -1.
Step-by-step explanation:
Answer: (24,-9)
(0,9)
(4,6)
Step-by-step explanation:
3x + 4y = 36
Using (3,-2) will be:
= 3(3) + 4(-2)
= 9 - 8 = 1
Using (1,7) will be
= 3(1) + 4(7)
= 3 + 28 = 31
Using (0,0) equals to 0
Using (24,-9) will be:
= 3(24) +4( -9)
= 72 - 36 = 36
Using (0,9) will be:
= 3(0) + 4(9)
= 0 + 36 = 36
Using (4,6) will be:
3(4) + 4(6)
= 12 + 24
= 36
Using (-12,18) will be:
= 3(-12) + 4(-18)
= -36 - 72
= -108
The correct options are (24,-9), (0,9 and (4,6)
Answer:
a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14
b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5
c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16
d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16
e) cannot decipher the equation
f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21
