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MissTica
2 years ago
7

$50 toolset; 10% markup

Mathematics
1 answer:
Margarita [4]2 years ago
7 0

Answer:

10% of 50 is 5 dollars up, so will be $55

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Determine the largest integer value of x in the solution of the following inequality. -3x +1> 7
tino4ka555 [31]

Answer:

x<1/3

Step-by-step explanation:

5 0
3 years ago
Round the number to the place indicated.<br> Round to the nearest tenth: 1.4511
Evgen [1.6K]
1.500 since 45 rounds to 50
8 0
3 years ago
I did my best to fit it all lol, can someone please help? &lt;3
pav-90 [236]

Answer:

8a. 0 8b. -1/3

Step-by-step explanation:

slope formula: \frac{y_{2} - y_{1}}{x_{2} - x{1}}

8a. => (8 + 12)/(17 - 17) = 20/0 = 0

8b. (1 + 2)/(-3 - 6) = 3/-9 = - 1/3

3 0
2 years ago
Read 2 more answers
Suppose that an individual has a body fat percentage of 14.5% and weighs 171 pounds. How many pounds of his weight is made up of
scZoUnD [109]

Answer:

24.8 lbs

Step-by-step explanation:

14.5% is 0.145 in decimal and then you multiply it by the weight, and get the answer

0.145x171=24.8 lbs

3 0
3 years ago
Claim: The standard deviation of pulse rates of adult males is less than 11 bpm. For a random sample of 132 adult​ males, the pu
seraphim [82]

Answer:

\chi^2 =\frac{132-1}{121} 114.49 =123.952

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=132 represent the sample size

\alpha represent the confidence level  

s^2 =10.7^2 =114.49 represent the sample variance obtained

\sigma^2_0 =11^2=121 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \geq 121

Alternative hypothesis: \sigma^2

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{132-1}{121} 114.49 =123.952

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 131. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(123.952,131,TRUE)"

5 0
2 years ago
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