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3 years ago

12

A plumber needs to replace 20 feet of copper piping. When he gets to the supply store the lengths are given in meters. How many

meters of piping does he need to purchase?

1 answer:

KengaRu [80]3 years ago

3 0

The Meters of piping Needed to be purchased by the plumber are 6.096 meters.
HOPE I HELPED!
-"UNICORN"

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Determine the domain on which the following function is decreasing.

dexar [7]

The way I remember domain(the distance where x is shown) and range(the distance where y is shown) is that it lines up with an ordered pair. It sounds wrong to say range and domain, just like it sounds wrong to say y,x.

the answer for this would be [0,11]

7 0

3 years ago

Evaluate the summation of negative 5 n minus 1, from n equals 3 to 12..

NARA [144]

The summation of negative 5 n minus 1, from n equals 3 to 12 can be expressed as

n = 3/12

substitute the value of n to the equatio

-5n – 1

-5( 3/12 ) -1

-9/4

5 0

3 years ago

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

<u><em /></u>

<u><em>Let </em></u> $\bar X$ <u><em> = sample mean heights</em></u>

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)

= <u>0.99492 or 99.5%</u>

<em>The above probability is calculated by looking at the value of x = 2.57 in the z table which has an area of 0.99492.</em>

<em />

Therefore, 99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

3 0

3 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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3 years ago

Express… As a limit of a right Reimann sum

elixir [45]

Answer:

Step-by-step explanation:

ohhhh yeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

hhahahahahahahahahahaahhhahahaahahahahhahahahah⇒⇒⇒⇒⇒⇵⇵∀∝×÷±≈≠∑Фω∞≅≡≡⇄⇄⇆⇆∡㏒㏑ somethin

5 0

1 year ago