Answer:
$3.97x + $10 < (or equal to) $25
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Recall that we need to use the equation y=a(x-h)^2+k. This means that h=-2 instead of 2 otherwise it would've been (x-2)^2-6. So Renaldo made the mistake of identifying h as 2 instead of -2. The second mistake Renaldo made is that since k=-6, there should be a vertical shift of 6 units down not 2.
5(3x-1)
(x-3)(x-2)
I don't know if you want working out or an explanation? Or if it's too late, sorry.
Answer:
Solution : (15, - 11)
Step-by-step explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )

Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :

Step # 1 : Swap the first and second matrix rows,

Step # 2 : Cancel leading coefficient in row 2 through
,

Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.

As you can see our solution is x = 15, y = - 11 or (15, - 11).
Open circle with an arrow to the left of the number line with the circle on 1.5 in the middle of 1 and 2