What is the value of 1/6

On a school playground, a math teacher draws a number line with values from 10 to 10. The distance between each

german

Answer:

12

<h3>Step-by-step explanation:</h3>

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

count the spaces between the two numbers

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4 0

3 years ago

Let a be a matrix. What must a and b be in order to define by t(x)ax?.

alisha [4.7K]

I am still not getting my phone back to my computer and my phone and I am trying to find out what

4 0

2 years ago

I need help can you help me please

ozzi

Just multiple them together and u get 693

6 0

3 years ago

A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

6 0

3 years ago

3. Factory farming funk - The US Environmental Protection Agency (EPA) recently reported that confined animal feeding operations

Vikentia [17]

Answer:

Step-by-step explanation:

Hello!

There was a survey made in Michigan asking the residents if they were in favor of or against the creation of standards to limit pollution by CAFOs.

Using the results of the survey the student that conducted it estimated the population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

The calculated 95% CI is [0,7752; 0,8248]

Interpretation: With a 95% confidence level you'd expect that the interval [0,7752; 0,8248] will include the true population proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

i.e. If you were to construct 100 confidence intervals, you'd expect 95 of them to contain the true value of the proportion of Michigan residents that are in favor of the creation of standards to limit pollution by CAFOs.

With this in mind:

Consider all of the following statements and determine which among them is incorrect

1) There is a 95% probability that the actual percent of Michigan residents in favor of pollution standards is between 77.52% and 82.48%. INCORRECT

2) Approximately 95% of MSU students favor pollution standards at a rate of 77.52% and 82.48%. INCORRECT

The confidence level is the probability that the interval will contain the true value of the parameter of interest and the bonds of the interval indicate the possible range of that parameter.

Also in 1) The parameter is not defined correctly, and in 2) the population of interest is incorrect.

3) If this study were repeated many times, we'd expect approximately 95% of future confidence intervals to contain the true rate at which Michigan residents favor the creation of pollution standards. CORRECT

4) With 95% confidence, we estimate the true rate at which Michigan residents favor the creation of pollution standards to be between 77.52% and 82.48%. CORRECT

I hope it helps!

6 0

3 years ago