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Vikki [24]
1 year ago
13

Choose the correct product of (8x − 4)(8x 4). 64x2 − 16 64x2 16 64x2 − 64x 16 64x2 64x 16

Mathematics
1 answer:
Sidana [21]1 year ago
3 0

The product of (8x - 4)(8x + 4) is 64x^2 - 16.

According to the given question.

We have an expression

(8x - 4)(8x + 4)

To find the product of the given expression we will use the identity of algebra

(a - b)(a + b) = a^2 - b^2

Therefore,

The product of (8x - 4)(8x + 4) is given by

(8x - 4)(8x + 4)

= (8x)^2 - (4)^2   (by using identity (a - b)(a + b) = a^2 - b^2)

= 64x^2 - 16

Hence, the product of (8x - 4)(8x + 4) is 64x^2 - 16.

Find out more information about how to find product here:

brainly.com/question/16950315

#SPJ4

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An arithmetic sequence is defined by the general term tn = -5 + (n - 1)78, where n ∈N and n ≥ 1. What is the recursive formula o
GrogVix [38]

\text{The general term of an arithmetic sequence:}\ a_n=a_1+(n-1)d\\\\a_n-n-th\ term\\a_1-first\ term\\d-common\ difference\\\\\text{We have}\ t_n=-5+(n-1)78.\ \text{Therefore}\ t_1=-5\ \text{and}\ d=78\\\\\text{The recursive formula of the sequence:}\\\\\left\{\begin{array}{ccc}t_1=-5\\t_n=t_{n-1}+78\end{array}\right

5 0
2 years ago
A random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6. A random sample of 17 su
Sladkaya [172]

Answer:

We conclude that there is no difference in potential mean sales per market in Region 1 and 2.

Step-by-step explanation:

We are given that a random sample of 12 supermarkets from Region 1 had mean sales of 84 with a standard deviation of 6.6.

A random sample of 17 supermarkets from Region 2 had a mean sales of 78.3 with a standard deviation of 8.5.

Let \mu_1 = mean sales per market in Region 1.

\mu_2  = mean sales per market in Region 2.

So, Null Hypothesis, H_0 : \mu_1-\mu_2 = 0      {means that there is no difference in potential mean sales per market in Region 1 and 2}

Alternate Hypothesis, H_A : > \mu_1-\mu_2\neq 0      {means that there is a difference in potential mean sales per market in Region 1 and 2}

The test statistics that will be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

                            T.S.  =  \frac{(\bar X_1 -\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+ {\frac{1}{n_2}}} }   ~  t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean sales in Region 1 = 84

\bar X_2 = sample mean sales in Region 2 = 78.3

s_1  = sample standard deviation of sales in Region 1 = 6.6

s_2  = sample standard deviation of sales in Region 2 = 8.5

n_1 = sample of supermarkets from Region 1 = 12

n_2 = sample of supermarkets from Region 2 = 17

Also, s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times  s_2^{2}  }{n_1+n_2-2} }  = s_p=\sqrt{\frac{(12-1)\times 6.6^{2}+(17-1)\times  8.5^{2}  }{12+17-2} } = 7.782

So, <u><em>the test statistics</em></u> =  \frac{(84-78.3)-(0)}{7.782 \times \sqrt{\frac{1}{12}+ {\frac{1}{17}}} }  ~   t_2_7

                                   =  1.943  

The value of t-test statistics is 1.943.

 

Now, at a 0.02 level of significance, the t table  gives a critical value of -2.472 and 2.473 at 27 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have<u><em> insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that there is no difference in potential mean sales per market in Region 1 and 2.

6 0
3 years ago
HELP ASAP PLEASE!!!!!
Musya8 [376]
The rule for inscribed angles and their corresponding arcs is that the measure of the angle is one-half that of the arc. Therefore, all we have to do is divide 68/2, which gets us an answer of D. 34.

Hope this helps!
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Answer:

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