Answer:
I don't see an SV in the examples.. I suspect these are the name plate numbers off of a transformer... but.. more context would really help
Explanation:
Answer:
Her performance over the course of a season.
Explanation:
An athlete is signed for a season. These days each aspect of an athlete is noted through the effective use of the best technology. However, for detailed study, one or several plays, and certainly not the second half of a game is enough. It's required to collect the details for a complete season. And that is possible, as an athlete is hired for a season. And through such a detailed data set of a complete season, we can now train a machine as well, and it will let the athlete know where she is going wrong. And thus she can improve and remove those faults from her game, and become a better athlete. And even for a coach, one complete season is required, though when he has not seen her playing before that season. It's assumed that this is her first season. All the options mentioned are good, but the best is certainly the one with complete details, and that is a complete season. The rest is good but not the best.
Answer: USB-C
I am 99.5% sure bcuz Im about 90 % because HDMI goes into TVs and stuff
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
Following is the code in python language
team_names = ('Rockets','Raptors','Warriors','Celtics')#holding the string value
print(team_names[0],team_names[1],team_names[2],team_names[3])#display
Output:
Rockets Raptors Warriors Celtics
Explanation:
Following is the description of above statement .
- Create a dictionary "team_names" that is holding the string value Rockets Raptors Warriors and Celtics.
- Finally we used the print function in that function we pass the index of corresponding dictionary i.e team_names[0] . it will display the first index value similarly we pass team_names[1], team_names[2] team_names[3].