Answer:
Any curved surface of a 3d object..
Answer:
A recursive function known as double-digit is a function that accepts as a parameter and returns the integer that is obtained by changing each digit with double digits. For example 425 should be return as 442255.
In the given scenario
the function will be as follow
If
def double_digits:
n < 0:
return -1 * double_digits ( -1 * n )
elif n = 0
return o
else:
result
double_digits ( n // 10 )
return int ( str ( result ) + str ( n % 10 ) + str ( n % 10 )
Test the function as follow
print ( double_digits ( 348 ) )
Result
334488
Test the function as follow
print ( double_digits ( 0 ) )
Result
0
Test the function as follow
print ( double_digits ( -789 ) )
Result
-778899
Idk sorry the awnser might be 123
Answer:
things is the correct answer
Answer:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double num1, num2, num3, num4, num5, sum = 0;
cout << "Input: ";
cin >> num1 >> num2 >> num3 >> num4 >> num5;
sum = num1 + num2 + num3 + num4 + num5;
cout << "Output: " << static_cast<int>(round(sum)) << endl;
return 0;
}
Explanation:
Include cmath to use the round function
Declare the variables
Get the five numbers from the user
Sum them and assign the result to the sum
Round the sum using the round function, and convert the sum to an integer using static_cast statement
Print the sum