4 years ago

Click on the solution set below until the correct one is displayed.

Mathematics

2 answers:

Llana [10]4 years ago

8 0

Answer:

point in Quadrant I

Step-by-step explanation:

SIZIF [17.4K]4 years ago

5 0

Answer:

{point in Quadrant II}

Step-by-step explanation:

The lines are headed toward each other in Quadrant II as x gets more negative. They will eventually intersect in that quadrant, giving one point as the solution to the two equations.

You might be interested in

Consider the function f(x, y) = x2 + xy + y2 defined on the unit disc, namely, D = {(x, y)| x2 + y2 ≤ 1}. Use the method of Lagr

a_sh-v [17]

Answer:________________________________________

Step-by-step explanation:

5 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20" id="TexFormula1" title=" \sqrt[3]{x - 1} " alt=" \sqrt[3]

shusha [124]

So the -1 is under the check mark too?

7 0

3 years ago

Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.

Sedaia [141]

The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x.

3 0

4 years ago

Please help asap

mixer [17]

13cm is the answer i hope this helps you!!!!!!!

6 0

3 years ago

Read 2 more answers

The function f(x)=x^2-12x+5written in vertex form is f(x)=(x-6)^2-31what are the coordinates of the vertex

schepotkina [342]

The vertex to this question is (6, -31)

5 0

3 years ago