This question is incomplete, the complete question is;
For integers a, b and k, we know that a > 12, b < 20 and a < b. If b=7k, what is the value of k ?
Answer: the value of k = 2
Step-by-step explanation:
Given that;
a > 12
b < 20
a < b
If b = 7k
Now if k = 1 {b = 7k = 7}
b would be equal to 7 but b has to be greater than 20
IT CANT BE
if k = 2 { b = 7k = 14}
b would be equal to 14, a is greater than 12, b has to be less than b; 14 < 20,
a has to be less than than b ( 12 < 14 )
IT IS
if k = 3 {b = 7k = 21}
b would be equal to 21, so b is greater than 20 and a is less than 21
IT CANT BE
Therefore the value of k = 2
- Two angles that are complements of each other add to equal 90 degrees (they are complementary angles).
- One angle measures x degrees.
- The other angle measures 25 more than 4 times the angle that measures x degrees; it measures 4x + 25 degrees.
To find x, set the sum of these expressions (x and 4x + 25) equal to 90 and solve algebraically for x.
90 = x + (4x + 25)
90 = x + 4x + 25
90 = 5x + 25
65 = 5x
13 = x
If you wanted to find the measure of angle x, you'd substitute 13 for x in its expression, 4x + 25.
4x + 25
4(13) + 25
52 + 25
77
Answer:
x = 13
m∠x = 77°
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer:
A (i) impossible, because the card D doesn't exist.
(ii) evens, because the number of vowel cards and consonant cards is equal
B (i) 62 - 24 - 13 - 16 = 9
(ii) 24/62*100% = 38.7%
(iii) (13+16) / 62 * 100% = 46.77%