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Lera25 [3.4K]
3 years ago
12

Which expression is equivalent to (3x^2-7)?

Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

C. (10x^2-4)-(7x^2+3)

Step-by-step explanation:

In option A,

(2x^2-11)-(x^2+4)= 2x^2 - 11 - x^2 - 4 = x^2 -15

Since,

(x^2-15)\neq (3x^2-7)

⇒ Option A is incorrect.

In option B,

(5x^2-6)-(2x^2-1)= 5x^2-6-2x^2+1 = 3x^2 -5

Since,

(3x^2-5)\neq (3x^2-7)

⇒ Option B is incorrect.

In option C,

(10x^2-4)-(7x^2+3)= 10x^2-4-7x^2-3 = 3x^2 -7

⇒ Option C is correct.

In option D,

(15x^2-8)-(18x^2+1)= 15x^2-8-18x^2-1= -3x^2 -9

Since,

(-3x^2 -9)\neq (3x^2-7)

⇒ Option D is incorrect.

Dafna11 [192]3 years ago
4 0

C.\ (10x^2-4)-(7x^2+3)=10x^2-4-7x^2-3=(10x^2-7x^2)+(-4-3)=3x^2-7

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