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Alchen [17]
3 years ago
7

A teacher gives a test to a large group of students. The results are closely approximated by a normal curve. The mean is 74​, wi

th a standard deviation of 8. The teacher wishes to give​ A's to the top 8​% of the students and​ F's to the bottom 8​%. A grade of B is given to the next 16​%, with​ D's given similarly. All other students get​ C's. Find the bottom cutoff for a grade of C.
Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that a teacher  gives a test to a large group of students. The results are closely approximated by a normal curve

mu =74 and sigma =8

A grade starts from 100-8 = 92nd percentile

Z score for 92nd percentile = 1.405

X score = 74+8(1.405) = 85.24

--------------------

B cut off is to next 16%

Hence C would start for scores below 100-(8+16) = 76%

76th percentile = 0.705*8+74 =79.64

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A yoga studio sells monthly memberships. The function f(x) = −x2 + 50x − 264 models the profit in dollars, where x is the number
Keith_Richards [23]

Answer:

x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made.

Step-by-step explanation:

f(x) = −x² + 50x − 264

−x² + 50x − 264 = 0

-x² + 44x + 6x - 264 = 0

-x(x - 44) + 6(x - 44) = 0

(x - 44)(-x + 6) = 0

x = 6, 44

4 0
3 years ago
What is the value of x in the diagram below
Artyom0805 [142]

Answer:

D) 9

Step-by-step explanation:

Using proportions, we have

12/2 = 54/x

Cross multiplying, we have

12(x) = 2(54)

12x = 108

Divide both sides by 12:

12x/12 = 108/12

x = 9

7 0
3 years ago
Order from least to greatest<br><br>1/8, 11/12, 9/8​
zepelin [54]

Answer:

Step-by-step explanation:

First make the denominators the same.

Take the LCM of (8, 12 , 8) = 24

So,

      \frac{1}{8}, \frac{11}{12}, \frac{9}{8} \ becomes \  \frac{3}{24}, \frac{22}{24}, \frac{27}{24}

Order \ from \ least \ to \ greatest \ \\\\\frac{3}{24} <  \frac{22}{24} < \frac{27}{24}

That is,

           \frac{1}{8}, \frac{11}{12}, \frac{9}{8}

8 0
3 years ago
Equation of the line slope with slope -3 and the passes through (2,-1)
Anni [7]

<u>Answer: </u>

The equation of the line with slope -3 and passes through (2,-1) is y = -3x + 5

<u>Solution:</u>

In the question it is given that the line passes through the point (2,-1) with slope (m) = -3. We have to find out the point slope form and slope intercept form of the equation.

We know the point - slope form of an equation is given by  

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { Here } y_{1}=-1 \text { and } x_{1}=2 \text { and the slope } m=-3

Substituting the values in the point slope form of the equation we get

(y-(-1)) = -3(x-2)

(y+1) = -3 (x-2) is the point slope form of given line

We know the slope intercept form of a line is given by  

y = mx +c  

Here y = -1 , x = 2 and m = -3

Substituting the values in slope intercept form equation we get

-1 = (-3)2 + c

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⇒-1+6 = c

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4 0
3 years ago
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IgorLugansk [536]
What class is this for? I’ll help you but i don’t see a picture or anything. How many dogs were bought around the world or in one particular area?
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