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Eduardwww [97]
3 years ago
8

During with interval was the bicyclists speed the greatest?

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

check the picture below.

namely, which of those intervals has the steepest slope, recall slope = average rate of change.

now, from the picture, notice, those two there are the steepest, the other three are leaning too much to the "ground".

so, from those two, which is the steepest anyway?  let's check their slope.


\bf \stackrel{\textit{from the 6th to the 8th hour}}{(\stackrel{x_1}{6}~,~\stackrel{y_1}{104})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{146})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{146-104}{8-2}\implies \cfrac{42}{2}\implies 21~~\bigotimes \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \stackrel{\textit{from the 1st to the 2nd hour}}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{12})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{34})} \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{34-12}{2-1}\implies \cfrac{22}{1}\implies 22~~\checkmark

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Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

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This means that

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By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

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