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devlian [24]
3 years ago
7

10 POINTS PLEASE SOS IK TIMED

Mathematics
1 answer:
Korvikt [17]3 years ago
6 0

I honestly went by elimination so

Work:

Teacher = 4   Student = 2

A) 5 Teachers = 20 pizza     1 Student = 2    = 22

B) 4 Teachers= 16 Pizza      2 Student = 4     = 20

C) 3 Teachers = 12 Pizza     3 Student = 6       = 18

D) 2 Teachers = 8 Pizza   4 Student = 8      = 16

E) 1 Teacher = 4 Pizza     5 Student= 10     = 14

Answer

There are exactly 3 Teachers and 3 Students.  (Answer C)

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Find the length of AC Use that length to find the length of
Gekata [30.6K]

Answer:

1. AC = 5 cm

2. CD = 10.7 cm

Step-by-step explanation:

Looking at the left triangle, we see that AC is the side "opposite" of the angle given and AB is the "hypotenuse".

Which trigonometric ratio relates "opposite" to "hypotenuse"?

<em>Yes, that's SINE.</em>

<em />

So we can write:

Sin(30)=\frac{AC}{10}\\AC=10*Sin(30)

We know from 30-60-90 triangle, Sin(30) = 0.5, so we have:

AC=10*Sin(30)\\AC=10*0.5\\AC=5

Thus,

AC = 5 cm

Now, looking at right side triangle, we know AC, side "opposite" and we want to find CD, side "adjacent". Which trig ratio relates these 2 sides?

<em>Yes, that's tan!</em>

Thus we can write:

Tan(25)=\frac{5}{CD}\\CD=\frac{5}{Tan(25)}

Now using calculator, we get our answer to be:

CD = \frac{5}{Tan(25)}=10.7

So

CD = 10.7 cm

8 0
3 years ago
You have a coin collection of nickels and dimes containing 63 coins. If you have
xxTIMURxx [149]

Answer: 25 nickels

Step-by-step explanation:

EQUATIONS:

quantity: n + d = 63

value: 5n + 10d = 505

-------------------------

Divide thru the 2nd equation by 5 to get:

n + 2d = 101

----------------

Subtract that from the 1st equation:

-d = -38

d = 38 (# of dimes)

---------------

Substitute that into n+d=63 to solve for "n":

n + 38 = 63

n = 25 (# of nickels)

6 0
3 years ago
A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to
alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution

Let put some notation  

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference d_i=x_i-y_i and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093

The next step is calculate the degrees of freedom given by:

df=n-1=9-1=8

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of \alpha=1-0.95=0.05 and \alpha/2=0.025, so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.

We can use the following excel code to find it:"=T.INV(0.025;8)" or "=T.INV(1-0.025;8)". And we got t_{\alpha/2}=\pm 2.31

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Now we have everything in order to replace into formula (1):  

2-2.31\frac{4.093}{\sqrt{9}}=-1.152  

2+2.31\frac{4.093}{\sqrt{9}}=5.152  

So on this case the 95% confidence interval would be given by (-1.152;5.152).

-1.152 < \mu_{safe1}-\mu_{safe2}  

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for D contains 0.

5 0
3 years ago
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katovenus [111]

Answer: 1/2 o .5

Step-by-step explanation:

5 0
3 years ago
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Graph 2 + 3y = 6. Please hurry
vitfil [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
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