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4 years ago

Who can help me with number 2

Mathematics

1 answer:

ddd [48]4 years ago

8 0

Y = 1.75x + 25

This is because it will cost 1.75 for each extra page and 25 to get the book made and ship regardless of the number of pages.

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WILL GIVE BRAINLIEST

REY [17]

Answer:

-8g+24h-32k

Step-by-step explanation:

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4 years ago

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Anybody help me to solve this question.

Mumz [18]

Answer:

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP$

Step-by-step explanation:

Given that $(b-c)^2, (c-a)^2 , (a-b)^2$ are in AP

To prove: $\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}$ are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

$2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab$

Now

$\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc$

Which is the result of AP

Hence proved

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3 years ago

Damien bought a box of 28 cookies. At the end of the day, 3/5 of the cookies were uneaten. To determine how many cookies were ea

xeze [42]

It needs to be multiplied by 20%, aka 0.2 in decimal form

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3 years ago

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Lerok [7]

Answer:

It is B

Step-by-step explanation:

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3 years ago

Point C(x,y) moves 5 until right and 7 until down.

aliya0001 [1]

Answer: (x, y) → (x + 5, y - 7)

<u>Step-by-step explanation:</u>

left and right affect the x-value

up and down affect the y-value

5 to the right means "add 5" to the x-value --> x → x + 5

7 down means "subtract 7" from the y-value --> y → y - 7

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3 years ago