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2 years ago

5

In the lock (shown on picture), there are ten numbers to choose from the set of (0, 1, ..., 9) and we choose 4 of them. b How ma

ny ways are there to choose them from the set of (7, 8, 9) only?

1 answer:

nadya68 [22]2 years ago

3 0

Answer:

6

Step-by-step explanation:

since their are 3 numbers to choose from we do 3! or 3*2*1 which is 6.

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The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Dominik [7]

Answer:

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

Step-by-step explanation:

Given

$(x_1,y_1,z_1) = (1,3,-2)$

$(x_2,y_2,z_2) = (4,5,0)$

$(x_3,y_3,z_3) = (6,3,9)$

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

$C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))$

Substitute values of x and y in the given equation

$C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))$

$C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))$

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

<em>The above is the coordinate of the centroid</em>

8 0

2 years ago

The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

Slav-nsk [51]

Answer:

The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

➠ Radius of cylinder
➠ Diameter of cylinder

$\begin{gathered}\end{gathered}$

<u>USING</u><u> </u><u>FORMULAS</u> :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

$\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}$

➛ Csa = Curved surface area
➛ π = 22/7
➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$

Hence, the diameter of the base of the cylinder is 2 cm.

$\rule{300}{2.5}$

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Yesterday, Julie’s bank account balance was –$10.28. She deposited some money into her account so that her balance is now $39.89

Tcecarenko [31]

10.28+39.89=50.17

hope this helps

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