For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

3 years ago

2x-7/4 - 1-x/6=17 What is the answer?

GalinKa [24]

The answer is X=237V22

4 0

3 years ago

Read 2 more answers

4G +4 equals 2G +8 what is the value of G

Oduvanchick [21]

4g + 4 = 2g + 8

4g - 2g = 8 - 4

2g = 4 / : 2

g = 2

7 0

3 years ago

Determine the period

mixas84 [53]

The period is 11

Explanation

8 0

3 years ago