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SCORPION-xisa [38]
3 years ago
12

Endpoints P(0, 0) and Q(8, 4). Find the coordinates of the midpoint of .

Mathematics
2 answers:
Anika [276]3 years ago
8 0

Answer:

(4, 2)

Step-by-step explanation:

(\frac{x_{1} + x_{2}}{2} , \frac{y_{1} + y_{2}}{2})

(\frac{8 + 0}{2} , \frac{4 + 0}{2})

(\frac{8}{2} , \frac{4}{2})

(4, 2)

azamat3 years ago
3 0

Answer:

(4,2)

Step-by-step explanation:

The midpoint of PQ = (x1+x2)/2 , (y1+y2)/2

                                 = (0+8)/2 , (0+4)/2

                                 = 8/2, 4/2

                                   =4,2

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A survey showed that 77​% of adults need correction​ (eyeglasses, contacts,​ surgery, etc.) for their eyesight. If 22 adults are
Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

Step-by-step explanation:

A survey showed that 77​% of adults need correction for their eyesight.

If 22 adults are randomly​ selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find P(x\leq 11)

P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)

Formula : P(x=r)=^nC_r p^r q^{n-r}

P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}

Using calculator

P(x\leq 11)=0.00512

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight​ correction .

3 0
3 years ago
find the smallest number by which 339 must be multiplied so that the product is a perfect cube. also find the cube root of the p
Murljashka [212]

Answer:

<em>The smallest number is 114921 and the cube root of the result is 339</em>

Step-by-step explanation:

The number 339 can be factored as:

339 = 3 * 113

Both factors are prime, thus to produce a perfect cube, we must multiply by each factor to the power of 2, that is:

3^2*113^2=114921

When we multiply 339 by 114921 we get 38958219, a perfect cube which cube root is 339.

Thus, the smallest number is 114921 and the cube root of the result is 339

4 0
3 years ago
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