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BaLLatris [955]
3 years ago
9

What the value of the expression? (11 - 4) x (6 + 5)

Mathematics
2 answers:
Darya [45]3 years ago
8 0
(11 - 4) (6 + 5) =
(7) (11) =
77
Tems11 [23]3 years ago
7 0
Numbers 77 answer 77 answer 77
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Leah knit a scarf that is 130 centimeters long, Theo knit a scarf that is 4/3 as long
Delvig [45]

Answer: Theo's scarf is  173 + 1/3 centimeters long.

Step-by-step explanation:

The scarf of Leah is 130 centimeters long.

The one of Theo is 4/3 as long as the one of Leah, then we have that the length of the scarf of Theo is:

Lenght = (4/3)*130 cm =(4*130)/3 cm =520/3 cm  

Now, we know that if all the digits of a number add up to a multiple of 3, that number is divisible by 3.

520/3 = (519 + 1)/3 = 519/3 + 1/3 = 173 + 1/3

Theo's scarf is  173 + 1/3 centimeters long.

3 0
3 years ago
casandra is traning for a 10 mile race. on the first day of training she runs 4 miles, each day after that she adds on 0.5 mile
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On the ninth day. Y=0.5x + 4
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3 years ago
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Mr. Smith's first test's data: 55, 42, 78, 99, 69, 83, 74, 83, 97. The third step in creating a Box-and-Whisker plot is to deter
Serga [27]
The value of Q3 is 4 i think.
7 0
3 years ago
Read 2 more answers
NEED HELP ASAP!!
dusya [7]

Answer Is set A

y = 3x + 3

y = 3(0) + 3

y = 0

(0,3)

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5 0
4 years ago
A city in the Pacific Northwest recorded its highest temperature at 91 degrees F and its lowest temperature at 12 degrees F for
docker41 [41]

Answer:

(A)12-19

Step-by-step explanation:

To construct a frequency distribution, we follow the steps below.

1. Find the largest and smallest values.

91 and 12 respectively

Compute the Range = Maximum - Minimum=91-12=79

2. Determine the number of classes desired.

In this case, we desire 10 classes

3. Next, we find the class width by dividing the range by the number of classes and rounding up.

79÷10 = 7.9

Rounded Up, Class Width=8

4. Pick a suitable starting point less than or equal to the minimum value.

Since our minimum value is 12, we pick a class starting with 12 and give a class width of 8.

Therefore the upper and lower limits of the first class is given as:

12-19.

7 0
3 years ago
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