Since she drove 60.8miles per hour(182.4÷3=60.8)
then she would drive 668.8 miles in 11 hours
(60.8×11=668.8
Answer:
y≥-4 or (-4,∞)
Step-by-step explanation:
Answer:
$14.8
Step-by-step explanation:
There is a mistype in the question. It should say: ... <em>si cada uno de ellos hicieron una contribución de </em><em>dieciseis</em><em> pesos...</em>
So if everybody contributes $14, they make a total of 14*x, where x denotes the number of students. In this scenario, $4 are left, calling y to the cost of the trip, then:
14*x = y - 4 (eq. 1)
In the other scenario, everybody contributes $16 and $6 are in excess, so
16*x = y + 6 (eq. 2)
subtracting eq. 1 to eq. 2:
16*x - 14*x = y + 6 - (y - 4)
2*x = y + 6 - y + 4
2*x = 10
x = 10/2 = 5
Replacing this value in eq. 1:
14*5 = y - 4
70 + 4 = y
y = $74
If every student pays: 74/5 = $14.8, then they would get altogether the exact cost of the trip
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
Answer:
the sinθ is 4√17 / 53.6
Step-by-step explanation:
All the steps are on the image :)
