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natta225 [31]
3 years ago
10

At an uncontrolled intersection, you should yield to the car on the right. True or false.

Computers and Technology
2 answers:
algol [13]3 years ago
6 0

true .. hope this is correct .. sorry if it is wrong

Lubov Fominskaja [6]3 years ago
3 0
Right of way is easily remembered by yielding to the car on the right. It's true.
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What are files that are placed on a computer by some websites when the user visits the site?
Otrada [13]

Answer:

A: Cookies.

Explanation:

Usually you will get a message about the site using "cookies" to help user experience.

3 0
3 years ago
"when a dynamic web page is requested, the web server passes the request to"
nalin [4]
System operations of the website u are  asking to access
7 0
3 years ago
Write a program which accepts two integers from the user. Then it asks the user what he wants to do with those two numbers. If t
il63 [147K]

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// function to print choice menu

void menu()

{

   cout<<"A – Add the two numbers:"<<endl;

   cout<<"B – Subtract the second number from the first number:"<<endl;

   cout<<"C – Multiply the first number by the second number:"<<endl;

   cout<<"D – Divide the first number by the second number:"<<endl;

   cout<<"Q – End the operation:"<<endl;

}

// driver function

int main()

{

// variables

int x,y;

char ch;

int flag=1;

do{

   cout<<"Enter first number:";

   // read first number

   cin>>x;

   cout<<"Enter second number:";

   // read second number

   cin>>y;

   // call menu function

   menu();

   cout<<"Enter your choice:";

   // read choice

   cin>>ch;

   switch(ch)

   {

       case 'A':

       case 'a':

       cout<<"Addition of two numbers is:"<<(x+y)<<endl;

       break;

       case 'B':

       case 'b':

       cout<<"Subtract the second from the first is:"<<(x-y)<<endl;

       break;

       case 'C':

       case 'c':

       cout<<"Multiplication of two numbers is:"<<(x*y)<<endl;

       break;

       case 'D':

       case 'd':

       cout<<"Division the first by the second is:"<<(x/y)<<endl;

       break;

       case 'Q':

       case 'q':

       flag=0;

   }

   if(flag==0)

   break;

   

}while(ch!='Q'||ch!='q');

return 0;

}

Explanation:

Read two numbers from user.Then read the choice for operation on both the numbers. Then print the choices of operation by calling menu() function.If choice is "A"  then print Addition of both.if choice is "B" then print subtraction of second from  first number.if choice is "C" then print the multiplication of both numbers.If choice is "D" then print division of first by second.If the choice is "Q" then quit the operation. Repeat this until user's choice is "Q".

Output:

Enter first number:6                                                                                                      

Enter second number:2                                                                                                      

A – Add the two numbers:                                                                                                  

B – Subtract the second number from the first number:                                                                      

C – Multiply the first number by the second number:                                                                        

D – Divide the first number by the second number:                                                                          

Q – End the operation:                                                                                                    

Enter your choice:A                                                                                                        

Addition of two numbers is:8                                                                                              

Enter first number:8                                                                                                      

Enter second number:2                                                                                                      

A – Add the two numbers:                                                                                                  

B – Subtract the second number from the first number:                                                                      

C – Multiply the first number by the second number:                                                                        

D – Divide the first number by the second number:                                                                          

Q – End the operation:                                                                                                    

Enter your choice:Q      

3 0
3 years ago
Your son is complaining that his smartphone is broken. He tells you that he cannot connect to the internet, nor can he make or r
ycow [4]

Answer:

the correct and only reasonable answer is option B

3 0
2 years ago
Suppose the RAM for a certain computer has 256M words, where each word is 16 bits long.What is the capacity of the memory expres
bezimeni [28]

Answer:

The RAM capacity expressed in bytes is

512 million bytes

Explanation:

a) Data and Calculations:

RAM contains 256m words

Each word = 16 bits

1 bit = 0.125 byte

This means that each word will have 2 (16 * 0.125) bytes

Therefore, the RAM contains 256m * 2 = 512 million bytes

b) A bit is 0.125 bytes and a byte is eight times bigger than a bit.  This implies that there are eight megabits in every megabyte, and one gigabyte is eight times bigger than one gigabit.  The 512 million bytes above are about 488.3 gigabytes, since 1 gigabyte equals 1,024 megabytes or 1,046,576 kilobytes.

6 0
3 years ago
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