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Basile [38]
3 years ago
15

How do you do this math problem

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Distance formula (See attachment below)

100 + 144

square root 244

15.620

Round to the nearest tenth

15.6

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The diameter of a sphere with a volume of 121.5 cubic mm is ___ mm.
Scorpion4ik [409]

Answer:

Diameter= 6.15

Step-by-step explanation:

Like the radius explanation but multiply the answer by 2.

7 0
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7. The area of a square piece of cardboard is 70 cm2. What is the
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Answer:

8.3 cm

Step-by-step explanation:

<h2>so area of a square= side×side</h2><h2>since all sides are equal in a square</h2><h2>so= s×s=70cm²</h2><h2>√s²=√70</h2><h2>s=8.3 cm</h2>
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What value in place of the question mark makes the polynomial below a perfect square trinomial x^2+24x+?
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D

Step-by-step explanation:

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3 years ago
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Zohar is using scissors to cut a rectangle with a length of 5x – 2 and a width of 3x + 1 out of a larger piece of paper. The per
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The total distance she will need to cut is 62 centimeters. Work shown: 1) simplify original equation- 10x-4+6x+2( 40-4+24+2) 2) solve equation: 36+24+2 3) continue to solve: 38+24= 62. Now you have your answer!!
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A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
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Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

For x=57, we have

z=\dfrac{57-63.2}{2.4}\approx-2.58

For x=74, we have

z=\dfrac{74-63.2}{2.4}\approx4.5

Now, by using the standard normal distribution table, we have

The probability of women meeting the height requirement :-

P(-2.58

Hence, the percentage of women meeting the height requirement = 99.51%

8 0
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