A=140° r=16 ft calculate the arc length s and area a for each of the sectors
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11. Equation of hyperbola having vertices at (0, ±6) and foci at (0, ±9).
is given by
also b²= c²-a²
b²=81-36
b²=45
So, Equation becomes ,
Option (D) is correct.
12.Vertices (0, ± 4), Asymptotes = ±1/4.x
equation of asymptote is given by,
So a=4 and b=16,
So , equation becomes
Option (B) is correct.
13. x= t-3, and y = t²+ 5
Replace t by x+3, we get
y= (x+3)² +5
y=x²+ 6x +14
Option (A) is correct.
14. Polar coordinates is given by (r,∅)
Polar coordinates of point is (3, 2π/3)
So, r =3, ∅ =2π/3
x= r cos∅ and y = r sin∅
x=3 Cos (2π/3) and y= 3 Sin (2π/3)
x= -3/2 and y=3√3/2
Option (A) is correct.
14. Polar coordinate is given by (r,∅)
Here , r=1, and ∅ = -π/6
x= r Cos ∅ and y =r Sin∅
x= 1 Cos (-π/6) and y= 1 Sin (-π/6)
x =√3/2 and y =1/2
Option (B) which is B) (1, negative pi divided by 6 + 2nπ) or (-1, negative pi divided by 6 + 2nπ) is correct.
16. Two pairs of polar coordinates for the point (4, 4) with 0° ≤ θ < 360°.
is option (B) which is B) (4 square root 2 , 45°), (-4 square root 2 , 225°).
17. A circular graph with inner loop on the left of a limacon curve is given by
r = a + b Cos∅.
In this case a> b.
So , Option (D) r = 4 + cos θ as well as (A) r = 3 + 2 cos θ looks correct.
18. Equation of limacon curve is given by r = -2 + 3 cos θ, here , a<b
So it is symmetric about y-axis only.Option (B) is correct.
By using the PEMDAS order of operations, we get 3(6+7) = 39.
The equation be 3(6+7) then the correct answer is 34.
<h3>What is PEMDAS order of operations?</h3>The order of operations exists as a law that describes the proper sequence of stages for estimating a math expression. We can recognize the order utilizing PEMDAS: Parentheses, Exponents, Multiplication, Division (from left to right), Addition, and Subtraction (from left to right).
Given: 3(6+7)
By using the PEMDAS order of operations, we get
(6+7) = 13
Then we get
3(6+7) = 3 13
= 39.
Therefore, the value of 3(6+7) = 39.
To learn more about PEMDAS order of operations refer to:
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