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STatiana [176]
3 years ago
15

BRAINLIEST FOR WHOEVER SOVLES FIRST AND GIVES A GOOD REASON.

Mathematics
1 answer:
natulia [17]3 years ago
6 0
X=60
That’s the answer

What I did to get it
(3x-60)=120
+60. +60
3x =180
————. = 60
3

X=60
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Find an equation of the line that is perpendicular to the graph of 2x+5y=5 and contains the point of intersection of the graphs
gavmur [86]

Answer:

  5(x+1) -2(y-3) = 0

Step-by-step explanation:

For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...

  b(x-h) -a(y-k) = 0

A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...

  5(x+1) -2(y-3) = 0

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In the attached graph, the requested line is shown in black.

3 0
3 years ago
Find f (-2) if f (x)=4x+1
telo118 [61]

Answer:

f(-2)=4(-2)+1= 7

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Correct Answers only please!
Tcecarenko [31]

Answer:

C. $97

Step-by-step explanation:

The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.

average wage for 15 days = (sum of wages for the 15 days)/15

The amount of wages during a number of days is the product of the average wage of those days and the number of days.

First 7 days:

average wage: $87

number of days: 7

total wages in first 7 days = 7 * $87/day = $609

Last 7 days:

average wage: $92

number of days: 7

total wages in last 7 days = 7 * $92/day = $644

8th day:

wages of the 8th day is unknown, so we let x = wages of the 8th day

total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)

total wages of 15 days = 609 + x + 644 = x + 1253

average wage for 15 days = (sum of wages for the 15 days)/15

average wage for 15 days = (x + 1253)/15

We are told the average for the 15 days is $90/day.

(x + 1253)/15 = 90

Multiply both sides by 15.

x + 1253 = 1350

Subtract 1253 from both sides.

x = 97

Answer: $97

3 0
3 years ago
A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises
Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft

Period = 12 hours

and we know that; period = 2π/b

so

12 = 2π/b

12b = 2π

b = 2π / 12

b = π/6

Standard equation for simple harmonic is; y = asin(bt)

we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

7 0
3 years ago
I will give Brainliest
ioda

Answer:

The volume(V) of gas will increase when the pressure of the gas decreases assuming all the other variables are held constant.

Step-by-step explanation:

 P = Pressure of the ideal gas

            V = Volume of the ideal gas

            n = Moles of the ideal gas

            R = Universal gas constant

            T = Temperature of the ideal gas

4 0
3 years ago
Read 2 more answers
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