Question

A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.

Answer 1

Answer:

cone volume=(1/3)hpir^2

d/2=r

d=12

d/2=12/2=6=r

V=120pi

120pi=(1/3)hpi6^2

120pi=(1/3)hpi36

120pi=12hpi

divide both sides by pi

120=12h

divide 12

10=h cm

if height and diameter is doubled aka height and radius are doubled

V=(1/3)(2h)pi(2r^2)

we want to see how it compares to V=(1/3)hpir^2

V=(1/3)(2h)pi(2r^2)

V=2(1/3)(h)pi4r^2

V=8((1/3)hpir^2)

the volume is increased by 8 times

blanks are

10

8

Step-by-step explanation: