Step-by-step explanation:
1/625×15625
We wil add power 2 as shown in the bracket
It will be 1/390625×244140625=625
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The number of permutations of the 4 different letters, taken two at a time, is given by:
1/9-22/9-5/9
-21/9-5/9
-26/9
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer