The coefficients of x and y in the first equation are 3 and -4, respectively.
The coefficients of x and y in the second equation are 1 and 6, respectively.
The coefficient matrix lists these coefficients in order on successive rows, so it will be ...
![\left[\begin{array}{cc}3&-4\\1&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%26-4%5C%5C1%266%5Cend%7Barray%7D%5Cright%5D)
Let n = the newsstand price. Then 0.30n = $29.99, and n = $99.97 for 12 issues. Dividing by 12: $99.97/0.30. The single-issue price at the newsstand is $8.33.
Answer:
2(d-vt)=-at^2
a=2(d-vt)/t^2
at^2=2(d-vt)
Step-by-step explanation:
Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is
displacement, v is final velocity, a is acceleration, and t is time.
Given the formula for calculating the displacement of a body as shown below;
d=vt - 1/2at^2
Where,
d = displacement
v = final velocity
a = acceleration
t = time
To make acceleration(a), the subject of the formula
Subtract vt from both sides of the equation
d=vt - 1/2at^2
d - vt=vt - vt - 1/2at^2
d - vt= -1/2at^2
2(d - vt) = -at^2
Divide both sides by t^2
2(d - vt) / t^2 = -at^2 / t^2
2(d - vt) / t^2 = -a
a= -2(d - vt) / t^2
a=2(vt - d) / t^2
2(vt-d)=at^2
x/9-7 is the answer to this problem
