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3 years ago

12

How do you interpret a slope and the y- intercept?

1 answer:

nexus9112 [7]3 years ago

8 0

The slope is rise over run, how many times you go up (or if down it'd be a negative) and over.
The y-intercept is what point on the y axis the line passes through

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Pleaseee helppppp..will give 15 pts

pickupchik [31]

I think square is the right answer

7 0

2 years ago

Please help and i will brainliestttt

Nutka1998 [239]

Answer:

All you need to do is substitute.

$-3+(-6)^2/ 9$

-3 + 36/9

-3 + 4

= 1

3 0

3 years ago

The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number

Whitepunk [10]

Answer:

The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number?

the number is 2.409

Step-by-step explanation:

based on the question;

let the number N

1/6 of N = (1/6)N

21/2 of N = ( 5/2)N

now, the sum of a number (N) 1/6 of that number(1/6)N , (5/2)N and 7 will be expressed as

N + ( 1/6)N + (5/2)N + 7 = 12 1/2

N + N/6 + 5N/2 + 7 = 25/2

find the lcm of the equation

we have;

(6N + N +15N + 42)/6= 25/2

(22N + 42)/6 = 25/2

Using cross multiplication we have

44N + 84 = 150

Collecting the like terms

44N = 150- 84

44N = 106

Divide both sides by 44

44N/44= 106/44

N = 2.409

3 0

3 years ago

Complete the statement below.

S_A_V [24]

Answer:

I would say 3, since you would need to move the decimal point up 3 times to get .0264

8 0

3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago