Question

(7^2)^x=1 solve for x

Answer 1

Answer:

x=0

Step-by-step explanation:

You are asked what is the number to be use as the exponent of $7^{2}$, in order to get as answer "1".

Use the property of exponents that sates that : $a^0=1$

In your case $a=7^2=49$ so the exponent "x"must be = 0 (zero)

Answer 2

Answer:

The value of x in the given equation is 0.

Solution:

We know that any number with power 0 is 1  $(a^{0}=1)$

As given,

$\left(7^{2}\right)^{x}=1$  

As per the formula, $(a^{m})^n = a^{m+n}$

Here a is 7; 2 is m and x is n.

On substituting the values,  

$(7)^{2\times x}=1$

$(7)^{2\times x}=7^{0}$ (//any power of 0 is 1)

Hence from both the side we get,

$(2\times x) = 0$

So, x = 0.