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WITCHER [35]
3 years ago
15

A transformation of ΔDEF results in ΔD'E'F'.

Mathematics
2 answers:
sladkih [1.3K]3 years ago
6 0

Answer:

Rotation

Step-by-step explanation:

A transformation of a triangle can be either dilation or reflection or rotation or a translation.

Dilation happens when a symmetric figure is formed with scale factor other than 1.  But here both triangles have same side length.  Hence no dilation

Reflection happens when it is reflected over a line as we see in a mirror. But here the two triangles are not looking as images on  a line.  Hence no reflection

Rotation is keeping the same shape but rotating through a certain angle.  Here DEF is rotated without disturbing its shape or size through a certain angle. Hence rotation is right

Translation is not right because there is no vertical or horizontal shift to get new triangle.

EastWind [94]3 years ago
6 0

Answer:

c

Step-by-step explanation:

The transformation is a rotation.

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(3x + 5)º<br> (6x + 13)°
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Answer: 18x2 + 69x + 65

Step-by-step explanation:

(3x + 5) (~6x + 13)

1. 3x(6x + 13) + 5(6x + 13)

2. 18x2 + 39x + 5(6x + 13)

3. 18x2 + 39x + 30 + 65

4. 18x2 + 69 + 65

6 0
2 years ago
Fill in the y-value for each box in the t-chart using the equation below !?
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Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? y = negative 6 (x minus 1) squared + 8 y = negative 6 (x + one-fo
mart [117]

Answer:

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

Step-by-step explanation:

Given:

y = -6x^2 + 3x + 2

Required

Rewrite in vertex form

The vertex form of an equation is in form of: y = a(x - h)^2+ k

Solving: y = -6x^2 + 3x + 2

Subtract 2 from both sides

y - 2 = -6x^2 + 3x + 2 - 2

y - 2 = -6x^2 + 3x

Factorize expression on the right hand side by dividing through by the coefficient of x²

y - 2 = -6(x^2 + \frac{3x}{-6})

y - 2 = -6(x^2 - \frac{3x}{6})

y - 2 = -6(x^2 - \frac{x}{2})

Get a perfect square of coefficient of x; then add to both sides

------------------------------------------------------------------------------------

<em>Rough work</em>

The coefficient of x is \frac{-1}{2}

It's square is (\frac{-1}{2})^2 = \frac{1}{4}

Adding inside the bracket of -6(x^2 - \frac{x}{2}) to give: -6(x^2 - \frac{x}{2} + \frac{1}{4})

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: -6(\frac{1}{4})

------------------------------------------------------------------------------------

The expression becomes

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y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

Factorize the expression on the right hand side

y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2

y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2

y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2

y - (\frac{7}{2})= -6(x - \frac{1}{2})^2

y  +\frac{7}{2} = -6(x - \frac{1}{2})^2

Make y the subject of formula

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

<em>Solved</em>

7 0
3 years ago
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Explanation:

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Area of the outer circle: π (10ft +  5 ft)² = π (15 ft)² = 225 π ft²

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Area of the ring  (sidewald) = 225π ft² - 100π ft² = 125π ft² = 392.699 ft²
6 0
3 years ago
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