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Anon25 [30]
3 years ago
12

Hey i made this so i could talk to new ppl

Mathematics
2 answers:
Gnom [1K]3 years ago
6 0

Answer:

heyyy im yanie

Step-by-step explanation:

MrMuchimi3 years ago
3 0

Answer:

ohhh sweet..................

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Find a value of x that makes the equation true:<br> -(-2x + 1) = 9 – 14x
luda_lava [24]

Answer:

x=0.625

Step-by-step explanation:

-(-2x+1)=9-14x

distribute:

2x-1=9-14x

add  1 to both sides

2x = 10-14x

add 14x to both sides

16x=10

divide by 16 to isolate x

x = 0.625

check:

-(-2(0.625)+1) = 9-14(0.625)

0.25 = 0.25

5 0
2 years ago
Read 2 more answers
Make a sketch of the cross section resulting from the slice shown in the right square pyramid below. Then, using complete senten
Assoli18 [71]

Answer:3

Step-by-step explanation:

38+s6$

6 0
3 years ago
what are the steps to answer this question? Jeff is baking a cake. The recipe says that he has to mix 32 grams of powder to the
Deffense [45]
Well what I would do first is to divide 128 by 32 which I do believe gets you 4. So now you know that 1 cup of powder can make 4 servings. So you now know that each serving only requires 1/4 cup of the powder.

So now we know Jeff went over so now we have Jeff added 2/3 and he only needs 1/4. I would now make them both equivalent by multiplying the numerator and denominator of 2/3 by 4 and the same for 1/4 but instead by 4 multiply it by 3 which you would get 2/3=8/12 and 1/4=3/12. Now subtract the two to get your answer.

8/12-3/12=5/12

Answer: He went over and he needs to remove 5/12 of the cup
5 0
3 years ago
Calculate the area of the square shown below (HARD)
sergey [27]
Check the picture below.

recall that in a square, all sides are equal, so if we make b = a, then we get that for one side, also recall that the area of a rectangle is length*width, so in this case,

\bf \stackrel{\textit{area of the square}}{\stackrel{length}{5\sqrt{2}}\cdot \stackrel{width}{5\sqrt{2}}}\implies 25(\sqrt{2})^2\implies 25\cdot 2\implies 50

7 0
3 years ago
Need help quick please. Find the area of the sector use 3.14 for pi
olga55 [171]

\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=9\\ \theta =120 \end{cases}\implies \begin{array}{llll} A=\cfrac{(120)\pi (9)^2}{360}\implies A=27\pi \\\\\\ \stackrel{using~\pi =3.14}{A\approx 84.8} \end{array}

7 0
2 years ago
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