Csc²x - 1
1/sin²x - 1
1/sin²x - sin²x / sin²x
(1 - sin²x) / sin²x
Recall that sin²x + cos²x = 1
So cos²x = 1 - sin²x
So we can replace numerator to cos²x
cos²x / sin²x
= cot²x
Final answer: cot²x
Answer:
10 9/10
10.9
109/10
they all should be correct. depends on what they're asking for though:)
Answer:
1. A. Quantitative data
B. Quantitative data
C. Qualitative data
D. Quantitative data
E. Qualitative data
F. Quantitative data
2.a. Yearly salaries: interval or ratio data
b. Employee numbers: interval or ratio data
c. Area codes : nominal data
d. The ages: interval or ratio data
e. Survey answers: ordinal data
f. IQ index: interval or ratio data
Explanation:
Qualitative data is data in the form of a quality such as a characteristic. It is usually a noun, such as whether a person is fair or dark in complexion. Quantitative data is data in form of quantity such as the amount in dollars of one's salary.
There are four levels of data measurement. They are: nominal data, ordinal data, interval data, and ratio data. Nominal and ordinal data are qualitative data while interval and ratio data are quantitative data.
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
