The probability of spinning a prime number and not flipping heads will be given as follows:
P(Prime)*P(Tails)
P(Prime)=3/5
P(Tails)=1/2
Thus
P(Prime) and P(Tails)
=3/5×1/2
=3/10
When we factor out something, we divide the factor by the equation. For example if we were to factor 3 out of 6, It will be 3(2). We got this answer by dividing 3 and 6. Using this concept:
![\frac{-1}{4}[( \frac{-1}{2} / \frac{-1}{4}) - ( \frac{5}{4} y / \frac{-1}{4})]](https://tex.z-dn.net/?f=%20%5Cfrac%7B-1%7D%7B4%7D%5B%28%20%5Cfrac%7B-1%7D%7B2%7D%20%2F%20%5Cfrac%7B-1%7D%7B4%7D%29%20-%20%28%20%5Cfrac%7B5%7D%7B4%7D%20y%20%2F%20%20%5Cfrac%7B-1%7D%7B4%7D%29%5D%20%20)
Simplifying:

Hope this helps!
-- The square of the shortest side . . . 16² = 256
-- The square of the medium side . . . 30² = 900
-- Their sum . . . (256 + 900) = <u>1,156</u>
-- The square of the longest side = 35² = <u>1,225</u>
1,156 and 1,225 are not equal, so these 3 numbers
<em>can</em> be the sides of a triangle, but it's not a right one.
The statement is <em>false</em>. (choice 'b')
Answer:
a
Step-by-step explanation: