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Lapatulllka [165]
3 years ago
9

Mira and Gus go to a concert. Mira buys a t-shirt for $30 plus 9% tax. Gus buys a poster for $25 plus 9% tax. Write the differen

ce in the amount that Mira and Gus paid, including tax. Round your answer to the nearest cent.
Mathematics
1 answer:
Kaylis [27]3 years ago
5 0
9% of $30 is $2.70. 9% of $25 is $2.25. Therefore, Mira pays $32.70 and Gus pays $27.25. 32.70-27.25=5.45. The difference in the amount of that Mira and Gus paid is $5.45.
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A plumber has a set fee for a house call and charges by the hour for repairs. The total cost of her services can be modeled by c
Lostsunrise [7]

Answer:

1, 2 and 3

Step-by-step explanation:

Let

t -----> the number of hours the job takes

C(t) -----> the total cost for the service

we have

C(t)=125t+95

This is the equation of a line in slope intercept form

where

The slope m is equal to m=125\ \frac{\$}{h}

The y-intercept is the point (0,95) ---> The cost is $95 for the value of t equal zero (fee)

therefore

<u><em>The statements that are true</em></u>

1 a house call fee costs $95

2 the plumber charges $125 per hour

3 the number of hours the job takes is represented by t

4 0
3 years ago
43, 52, 56, 47, 53, 60, 45, 40, 52, 48, 50<br> Find the median and mode of the following data.
Molodets [167]

Answer:

median = 50

mode = 52

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
4 years ago
ILL MARK U BRAINLIEST
Vladimir79 [104]

Answer:

-6x-16

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLZZ HELP I NEED AN EXPERT ANSWER
IceJOKER [234]
This trend line shows a general pattern, and since we are with biological samples this trend line will not always be true.  The outliers could be from either a genetic difference or an environmental difference that occured in the persons life.
4 0
3 years ago
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